洛谷 P4999 烦人的数学作业
数位dp
emmm其实就是个板子题,而且一点坑点都没有
直接看代码吧
别忘了开 (long long)
#include <iostream>
#include <cstdio>
#include <cstring>
#define ll long long
using namespace std;
const ll mod = 1e9 + 7;
ll l, r, len, T;
ll num[20];
ll dp[20][200][2]; //dp[len][sum][lim]:sum是各位数字之和,18位每一位最大是9,需要开18*9的数组
ll dfs(ll len, ll sum, ll lim){ //这边就是数位dp板子,emm不想写太多注释了,有问题可以去看我的其他博客,或者下面回复就好啦
if(!len) return sum;
if(dp[len][sum][lim] != -1) return dp[len][sum][lim]; //记忆化
ll res = lim ? num[len] : 9;
ll ans = 0;
for(ll i = 0; i <= res; i++)
ans = (ans + dfs(len - 1, sum + i, lim && (i == res))) % mod; //注意每一次计算都要取模,不然会被卡QWQ
return dp[len][sum][lim] = ans;
}
ll solve(ll x){
len = 0;
while(x){
num[++len] = x % 10;
x /= 10;
}
memset(dp, -1, sizeof(dp)); //dp初值为-1,防止计算过程中出现答案为0的情况
return dfs(len, 0, 1) % mod;
}
signed main(){
scanf("%lld", &T);
while(T--){
scanf("%lld%lld", &l, &r);
printf("%lld
", (solve(r) - solve(l - 1) + mod) % mod); //前缀和思想输出答案就好啦
}
return 0;
}
完结撒花~