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  • bzoj1668

    题解:

    简单dp

    注意最后往后面多取几个

    求个最小值

    代码:

    #include<bits/stdc++.h>
    using namespace std;
    const int N=60005;
    int n,m,f[N],a[N],b[N];
    int main()
    {
        scanf("%d%d",&n,&m);
        m+=5000;
        for (int i=1;i<=n;i++)scanf("%d%d",&a[i],&b[i]);
        memset(f,0x3f,sizeof f);
        f[0]=0;
        for (int i=1;i<=n;i++)
         for (int j=1;j<=m;j++)
          {
              f[j]=min(f[j],f[j+1]);
              if (j>=a[i])f[j]=min(f[j],f[j-a[i]]+b[i]);
          }
        for (int i=m;i;i--)
         f[i]=min(f[i],f[i+1]);  
        printf("%d",f[m-5000]);  
    }
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  • 原文地址:https://www.cnblogs.com/xuanyiming/p/8963957.html
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