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  • 19.2.1 [LeetCode 32] Longest Valid Parentheses

    Given a string containing just the characters '(' and ')', find the length of the longest valid (well-formed) parentheses substring.

    Example 1:

    Input: "(()"
    Output: 2
    Explanation: The longest valid parentheses substring is "()"
    

    Example 2:

    Input: ")()())"
    Output: 4
    Explanation: The longest valid parentheses substring is "()()"

    题意

    找最长的合法左右括号字符串

    题解

    这道题还蛮难的,一开始我的dp思路错误了(n3的复杂度真是不像话)

    把dp数组设为以当前索引值为末尾的合法字符串的长度就可以做了

     1 class Solution {
     2 public:
     3     int longestValidParentheses(string s) {
     4         int l = s.length();
     5         if (l < 2)return 0;
     6         int ans = 0;
     7         vector<int>dp;
     8         dp.resize(l);
     9         for (int i = 0; i < l; i++)
    10             dp[i] = 0;
    11         if (s[0] == '('&&s[1] == ')') {
    12             ans = 2;
    13             dp[1] = 2;
    14         }
    15         for (int i = 2; i < l; i++) {
    16             if (s[i] == '(')continue;
    17             if (s[i - 1] == '(')dp[i] = dp[i - 2] + 2;
    18             else {
    19                 int last = dp[i - 1];
    20                 if (i - last - 1 >= 0 && s[i - last - 1] == '(') {
    21                     dp[i] = last + 2;
    22                     if (i - last - 2 >= 0)
    23                         dp[i] += dp[i - last - 2];
    24                 }
    25             }
    26             ans = max(ans, dp[i]);
    27         }
    28         return ans;
    29     }
    30 };
    View Code
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  • 原文地址:https://www.cnblogs.com/yalphait/p/10346751.html
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