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  • 日期、天转换函数

     1 #include<iostream>
     2 using namespace std;
     3 
     4 static int daytable[2][13] ={
     5     {0,31,28,31,30,31,30,31,31,30,31,30,31},
     6     {0,31,29,31,30,31,30,31,31,30,31,30,31}
     7 };
     8 //返回某年某月的某天是该年的第多少天
     9 int day_of_year(int year ,int month,int day)
    10 {
    11     int i,leap;
    12     leap = ((year %4 ==0 && year%100 != 0 )||( year %400 == 0));
    13     for ( i  = 1; i < month;i++)
    14     {
    15         day += daytable[leap][i];
    16     }
    17 
    18     return day;
    19 }
    20 //返回某年的第多少天是该年的几月几号
    21 void month_day(int year ,int yearday ,int  *pmonth , int *pday)
    22 {
    23     int i,leap;
    24     leap = ((year %4 ==0 && year%100 != 0 )||( year %400 == 0));
    25     for (i = 1; yearday > daytable[leap][i] ; i++)
    26     {
    27         yearday -= daytable[leap][i]; 
    28     }
    29     *pmonth = i;
    30     *pday = yearday;
    31 }
    32 void main()
    33 {
    34     cout<<day_of_year(1988,8,2)<<endl;
    35     int month,day;
    36     month_day(1988,325,&month,&day);
    37     cout<<month<<""<<day<<"";
    38     cout<<endl;
    39 }
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  • 原文地址:https://www.cnblogs.com/yaoxc/p/3327274.html
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