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  • 138. Copy List with Random Pointer

    问题描述:

    A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null.

    Return a deep copy of the list.

    解题思路:

    1. 每个节点除了next指针还有random指针,所以我们可以用一个map将原节点和新节点形成一个1对1映射,然后在遍历节点找到其对应的random指向的节点。

    2. 直接复制每个节点并连接到节点后面:

      temp->next = p->next;

      p->next = temp;

      p = temp->next;

     然后复制random指针:

      temp = p->next;

      if(p->random)

        temp->random = p->random->next;

     然后断开成两个链表:

      temp = p->nextl

      p->next = temp->next;

      if(p->next)

        temp->next = p->next;

    跪服大神:水中的鱼

      

    代码:

    解法一:用map存储

    /**
     * Definition for singly-linked list with a random pointer.
     * struct RandomListNode {
     *     int label;
     *     RandomListNode *next, *random;
     *     RandomListNode(int x) : label(x), next(NULL), random(NULL) {}
     * };
     */
    class Solution {
    public:
        RandomListNode *copyRandomList(RandomListNode *head) {
            if(!head)
                return head;
            unordered_map<RandomListNode*, RandomListNode*> nodeMap;
            RandomListNode *p = head;
            RandomListNode *pre = p;
            while(p){
                RandomListNode *temp = new RandomListNode(p->label);
                nodeMap[p] = temp;
                if(p != head){
                    pre->next = temp;
                }
                pre = temp;
                p = p->next;
            }
            p = head;
            
            while(p){
                RandomListNode *node = nodeMap[p];
                if(p->random){
                    RandomListNode *rNode = nodeMap[p->random];
                    node->random = rNode;
                }
                p = p->next;
            }
            return nodeMap[head];
        }
    };

    解法二:在链表上进行操作。

    /**
     * Definition for singly-linked list with a random pointer.
     * struct RandomListNode {
     *     int label;
     *     RandomListNode *next, *random;
     *     RandomListNode(int x) : label(x), next(NULL), random(NULL) {}
     * };
     */
    class Solution {
    public:
        RandomListNode *copyRandomList(RandomListNode *head) {
            if(!head)
                return head;
            RandomListNode *p = head;
            //copy nodes and insert them
            while(p){
                RandomListNode *temp = new RandomListNode(p->label);
                temp->next = p->next;
                p->next = temp;
                p = temp->next;
            }
            //copy random pointer
            p = head;
            while(p){
                RandomListNode *temp = p->next;
                if(p->random){
                    temp->random = p->random->next;
                }
                p = temp->next;
            }
            
            RandomListNode *ret = head->next;
            p = head;
            RandomListNode *temp = ret;
            while(p){
                p->next = temp->next;
                if(temp->next){
                    temp->next = temp->next->next;
                }
                p = p->next;
                temp = temp->next;
            }
            return ret;
            
        }
    };
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  • 原文地址:https://www.cnblogs.com/yaoyudadudu/p/9124335.html
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