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  • 380. Insert Delete GetRandom O(1)

    问题描述:

    Design a data structure that supports all following operations in average O(1) time.

    1. insert(val): Inserts an item val to the set if not already present.
    2. remove(val): Removes an item val from the set if present.
    3. getRandom: Returns a random element from current set of elements. Each element must have the same probability of being returned.

    Example:

    // Init an empty set.
    RandomizedSet randomSet = new RandomizedSet();
    
    // Inserts 1 to the set. Returns true as 1 was inserted successfully.
    randomSet.insert(1);
    
    // Returns false as 2 does not exist in the set.
    randomSet.remove(2);
    
    // Inserts 2 to the set, returns true. Set now contains [1,2].
    randomSet.insert(2);
    
    // getRandom should return either 1 or 2 randomly.
    randomSet.getRandom();
    
    // Removes 1 from the set, returns true. Set now contains [2].
    randomSet.remove(1);
    
    // 2 was already in the set, so return false.
    randomSet.insert(2);
    
    // Since 2 is the only number in the set, getRandom always return 2.
    randomSet.getRandom();

    解题思路:

    因为要平均时间复杂度O(1),我们首先想到hashmap

    我们可以用hashmap来存储值和下标的健值对,同时用一个数组来存储值

    当我们需要插入时,可以首先通过hashmap判断是否存在,不存在再进行插入

    当我们需要删除时,首先也需要判断值是否存在:

      1. 若不存在返回false

      2. 若存在:

        a.首先将该元素与队尾元素交换(注意要更新队尾元素在hashmap中相应的下标)

        b.从数组中弹出最后一个元素,从map中删除该元素。

    代码:

    class RandomizedSet {
    public:
        /** Initialize your data structure here. */
        RandomizedSet() {
            
        }
        
        /** Inserts a value to the set. Returns true if the set did not already contain the specified element. */
        bool insert(int val) {
            if(m.count(val)) return false;
            m[val] = nums.size();
            nums.push_back(val);
            return true;
        }
        
        /** Removes a value from the set. Returns true if the set contained the specified element. */
        bool remove(int val) {
            if(!m.count(val)) return false;
            int end = nums.back();
            nums[m[val]] = end;
            m[end] = m[val];
            nums.pop_back();
            m.erase(val);
            return true;
        }
        
        /** Get a random element from the set. */
        int getRandom() {
            return nums[rand() % nums.size()];
        }
    private:
        vector<int> nums;
        unordered_map<int, int> m;
    };
    
    /**
     * Your RandomizedSet object will be instantiated and called as such:
     * RandomizedSet obj = new RandomizedSet();
     * bool param_1 = obj.insert(val);
     * bool param_2 = obj.remove(val);
     * int param_3 = obj.getRandom();
     */
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  • 原文地址:https://www.cnblogs.com/yaoyudadudu/p/9276186.html
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