| 6727064 | 2012-09-09 17:39:14 | Accepted | 4278 | 0MS | 212K | 853 B | G++ |
若代码有错，请指出^^
分析：
相当于将十进制转换为8进制。。。
View Code
1 #include <cstdio> 2 #include <cstring> 3 #include <algorithm> 4 5 using namespace std; 6 7 int n, m, l, ans; 8 int a[20]; 9 int p[11]; 10 11 int main() 12 { 13 p[0] = 1; 14 for (int i = 1; i < 11; ++i) p[i] = p[i-1] * 8; 15 while(scanf("%d", &n) == 1) { 16 if (n == 0) break; 17 l = 0; 18 m = n; 19 while(n) { 20 a[l++] = n % 10; 21 n /= 10; 22 } 23 for (int i = 0; i < l; ++i) { 24 if (a[i] == 4) a[i] = 3; 25 else if(a[i] == 5) a[i] = 4; 26 else if(a[i] == 6) a[i] = 5; 27 else if(a[i] == 7) a[i] = 6; 28 else if(a[i] == 9) a[i] = 7; 29 } 30 ans = 0; 31 for (int i = l-1; i >= 0; --i) 32 ans += a[i]*p[i]; 33 printf("%d: %d\n",m,ans); 34 35 } 36 37 return 0; 38 }