ArrayList 进阶方法之ListIterator

同样看的都是jdk1.8 中 ArrayList中的源码,整理测试一下而已
ListIterator(int index)方法，返回指定下标(包含该下标)后的值，此时index位置的元素就是新列表迭代器的第一个值。是不是感觉有点像substring(intindex)?
注：ArrayList类同时还提供了 listIterator() 方法，此方法与listIterator(int index)的差异是index=0,
此方法可以将ArrayList转换成ListIterator.
下面是源码及测试代码

源码：

    /**
     * Returns a list iterator over the elements in this list (in proper
     * sequence), starting at the specified position in the list.
     * The specified index indicates the first element that would be
     * returned by an initial call to {@link ListIterator#next next}.
     * An initial call to {@link ListIterator#previous previous} would
     * return the element with the specified index minus one.
     *
     * <p>The returned list iterator is <a href="#fail-fast"><i>fail-fast</i></a>.
     *
     * @throws IndexOutOfBoundsException {@inheritDoc}
     */
    public ListIterator<E> listIterator(int index) {
        if (index < 0 || index > size)
            throw new IndexOutOfBoundsException("Index: "+index);
        return new ListItr(index);
    }

测试代码：

import java.util.ListIterator;

public class listIteratorTest {
    public static void main(String[] args) {
        ArrayList<String> list = new ArrayList<String>();
        list.add("a");
        list.add("b");
        list.add("c");
        list.add("d");
        list.add("e");
        ListIterator<String> a = list.listIterator(2);
        while (a.hasNext()) {
            System.out.println(a.next());
        }

    }
}

运行结果：
c
d
e