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  • 广度优先搜索遍历连通图

    //广度优先搜索遍历连通图
    #include <iostream>
    using namespace std;
    
    #define MVNum 100
    #define MAXQSIZE 100
    
    typedef char VerTexType;
    typedef int ArcType;
    bool visited[MVNum];
    
    typedef struct {
    	VerTexType vexs[MVNum];
    		ArcType arcs[MVNum][MVNum];
    	int vexnum, arcnum;
    }Graph;
    
    typedef struct {
    	ArcType* base;
    	int front;
    	int rear;
    }sqQueue;
    
    void InitQueue(sqQueue& Q) {
    	Q.base = new ArcType[MAXQSIZE];
    	if (!Q.base)
    		exit(1);
    	Q.front = Q.rear = 0;
    }
    
    void EnQueue(sqQueue& Q, ArcType e) {
    	if ((Q.rear + 1) % MAXQSIZE == Q.front)
    		return;
    	Q.base[Q.rear] = e;
    	Q.rear = (Q.rear + 1) % MAXQSIZE;
    }
    
    bool QueueEmpty(sqQueue Q) {
    	if (Q.rear == Q.front)
    		return true;
    	return false;
    }
    
    void Dequeue(sqQueue& Q, ArcType& u) {
    	u = Q.base[Q.front];
    	Q.front = (Q.front + 1) % MAXQSIZE;
    }
    
    int LocateVex(Graph G, VerTexType v) {
    	for (int i = 0;i < G.vexnum;++i)
    		if (G.vexs[i] == v)
    			return i;
    	return -1;
    }
    
    void CreateUDN(Graph& G) {
    	int i, j, k;
    	cout << "请输入总顶点数,总边数,以空格隔开:";
    	cin >> G.vexnum >> G.arcnum;
    	cout << endl;
    	cout << "输入点的名称,如a" << endl;
    	for (i = 0;i < G.vexnum;++i) {
    		cout << "请输入第" << (i + 1) << "个点的名称:";
    		cin >> G.vexs[i];
    	}
    	cout << endl;
    	for (i = 0;i < G.vexnum;++i) {
    		for (j = 0;j < G.vexnum;++i)
    			G.arcs[i][j] = 0;
    	}
    	cout << "输入边依附的顶点,如a b" << endl;
    	for (k = 0;k < G.vexnum;k++) {
    		VerTexType v1, v2;
    		cout << "请输入第" << (k + 1) << "条边依附的顶点:";
    		cin >> v1 >> v2;
    		i = LocateVex(G, v1);
    		j = LocateVex(G, v2);
    		G.arcs[i][j] = 1;
    		G.arcs[j][i] = G.arcs[i][j];
    	}
    }
    
    int FirstAdjVex(Graph G, int v) {
    	int i;
    	for (i = 0;i < G.vexnum;++i) {
    		if (G.arcs[v][i] == 1 && visited[i] == false)
    			return i;
    	}
    	return -1;
    }
    
    int NextAdjVex(Graph G, int u, int w) {
    	int i;
    	for (i = w;i < G.vexnum;++i) {
    		if (G.arcs[u][i] == 1 && visited[i] == false)
    			return i;
    	}
    	return -1;
    }
    
    void BFS(Graph G, int v) {
    	sqQueue Q;
    	ArcType u;
    	ArcType w;
    
    	cout << G.vexs[v] << "  ";
    	visited[v] = true;
    	InitQueue(Q);
    	EnQueue(Q, v);
    	while (!QueueEmpty(Q)) {
    		Dequeue(Q, u);
    		for (w = FirstAdjVex(G, u);w >= 0;w = NextAdjVex(G, u, w)) {
    			if (!visited[w]) {
    				cout << G.vexs[w] << "   ";
    				visited[w] = true;
    				EnQueue(Q, w);
    			}
    		}
    	}
    }
    
    int main() {
    	cout << "广度优先搜索遍历连通图";
    	Graph G;
    	CreateUDN(G);
    	cout << endl;
    	cout << "无向连通图G创建完成!" << endl;
    
    	cout << "请输入遍历连通图的起始点:";
    	VerTexType c;
    	cin >> c;
    
    	int i;
    	for (i = 0;i < G.vexnum;++i) {
    		if (c == G.vexs[i])
    			break;
    	}
    	cout << endl;
    	while (i >= G.vexnum) {
    		cout << "该点不存在,请重新输入!" << endl;
    		cout << "请输入遍历连通图的起始点:";
    		cin >> c;
    		for (i = 0;i < G.vexnum;++i) {
    			if (c == G.vexs[i])
    				break;
    		}
    	}
    	cout << "广度优先搜索遍历连通图结果:" << endl;
    	BFS(G, i);
    
    	cout << endl;
    	return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/ygjzs/p/11877603.html
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