Educational Codeforces Round 7 B

Description

You are given the current time in 24-hour format hh:mm. Find and print the time after a minutes.

Note that you should find only the time after a minutes, see the examples to clarify the problem statement.

You can read more about 24-hour format here https://en.wikipedia.org/wiki/24-hour_clock.

Input

The first line contains the current time in the format hh:mm (0 ≤ hh < 24, 0 ≤ mm < 60). The hours and the minutes are given with two digits (the hours or the minutes less than 10 are given with the leading zeroes).

The second line contains integer a (0 ≤ a ≤ 104) — the number of the minutes passed.

Output

The only line should contain the time after a minutes in the format described in the input. Note that you should print exactly two digits for the hours and the minutes (add leading zeroes to the numbers if needed).

See the examples to check the input/output format.

Sample test(s)

input

23:59
10

output

00:09

input

20:20
121

output

22:21

input

10:10
0

output

10:10
一个简单的模拟

#include<stdio.h>
//#include<bits/stdc++.h>
#include<string.h>
#include<iostream>
#include<math.h>
#include<sstream>
#include<set>
#include<queue>
#include<map>
#include<vector>
#include<algorithm>
#include<limits.h>
#define inf 0x3fffffff
#define INF 0x3f3f3f3f
#define lson l,m,rt<<1
#define rson m+1,r,rt<<1|1
#define LL long long
#define ULL unsigned long long
using namespace std;
int t;
int n,m;
int sum,ans,flag;
int a,b,c,d;
int main()
{
    scanf("%d:%d",&a,&b);
    scanf("%d",&n);
    while(n--)
    {
        b++;
        if(b==60)
        {
            a++;
            b=0;
            if(a==24)
            {
                a=0;
            }
        }
    }
    printf("%02d:%02d",a,b);
    return 0;
}