zoukankan      html  css  js  c++  java
  • Experimental Educational Round: VolBIT Formulas Blitz N

    Description

    The Department of economic development of IT City created a model of city development till year 2100.

    To prepare report about growth perspectives it is required to get growth estimates from the model.

    To get the growth estimates it is required to solve a quadratic equation. Since the Department of economic development of IT City creates realistic models only, that quadratic equation has a solution, moreover there are exactly two different real roots.

    The greater of these roots corresponds to the optimistic scenario, the smaller one corresponds to the pessimistic one. Help to get these estimates, first the optimistic, then the pessimistic one.

    Input

    The only line of the input contains three integers a, b, c ( - 1000 ≤ a, b, c ≤ 1000) — the coefficients of ax2 + bx + c = 0 equation.

    Output

    In the first line output the greater of the equation roots, in the second line output the smaller one. Absolute or relative error should not be greater than 10- 6.

    Examples
    input
    1 30 200
    output
    -10.000000000000000
    -20.000000000000000
    简单求解
    其实注意一下a=0 然而测试数据并没有
    #include<stdio.h>
    //#include<bits/stdc++.h>
    #include<string.h>
    #include<iostream>
    #include<math.h>
    #include<sstream>
    #include<set>
    #include<queue>
    #include<map>
    #include<vector>
    #include<algorithm>
    #include<limits.h>
    #define inf 0x7fffffff
    #define INF 0x7fffffffffffffff
    #define lson l,m,rt<<1
    #define rson m+1,r,rt<<1|1
    #define LL long long
    #define ULL unsigned long long
    using namespace std;
    double v[2];
    int main()
    {
        double a,b,c,x1,x2,delta;
        cin>>a>>b>>c;
        if (a!=0)
        {
            delta=b*b-4*a*c;
            if (delta>=1e-9)
            {
                v[0]=(-b+sqrt(delta))/(2*a);
                v[1]=(-b-sqrt(delta))/(2*a);
                sort(v,v+2);
                printf("%.10f %.10f",v[1],v[0]);
            }
        }
        else
        {
            printf("%.10f %.10f",c/b,c/b);
        }
        return 0;
    }
    

      

  • 相关阅读:
    es集群的调优2
    es集群中kibana和es集群的高可用设置
    es集群中参数参数discovery.zen.minimum_master_nodes深度解析
    哔哩哔哩适合后端编程人员的elasticsearch快速实战教程学习总结
    Vue2-基本语句
    SpringBoot-ElasticSearch初使用
    Java-SSO单点登录的3种方式【待完善】
    Java-学习日记(函数式编程与@ControllerAdvice)
    SpringBoot-内置Tomcat启动原理
    Java-学习日记(Atomic,Volatile)
  • 原文地址:https://www.cnblogs.com/yinghualuowu/p/5215199.html
Copyright © 2011-2022 走看看