zoukankan      html  css  js  c++  java
  • Correct Solution?

    One cold winter evening Alice and her older brother Bob was sitting at home near the fireplace and giving each other interesting problems to solve. When it was Alice's turn, she told the number n to Bob and said:

    —Shuffle the digits in this number in order to obtain the smallest possible number without leading zeroes.

    —No problem! — said Bob and immediately gave her an answer.

    Alice said a random number, so she doesn't know whether Bob's answer is correct. Help her to find this out, because impatient brother is waiting for the verdict.

    Input

    The first line contains one integer n (0 ≤ n ≤ 109) without leading zeroes. The second lines contains one integer m (0 ≤ m ≤ 109) — Bob's answer, possibly with leading zeroes.

    Output

    Print OK if Bob's answer is correct and WRONG_ANSWER otherwise.

    Examples

    Input
    3310
    1033
    Output
    OK
    Input
    4
    5
    Output
    WRONG_ANSWER
    两组数,要求第二组数为第一组中数字组成的最小的且第一位不为0的数;
    #include<bits/stdc++.h>
    using namespace std;
    const int maxn=1e7;
    char a[maxn],b[maxn];
    int main()
    {
        int k=0;
        scanf("%s%s",a,b);
        char t;
        int len=strlen(a);
        sort(a,a+len);
        if((a[0]-'0')!=0)
        {
            if(strcmp(a,b)==0)
              cout<<"OK"<<endl;
            else
              cout<<"WRONG_ANSWER"<<endl;
        }
        if((a[0]-'0')==0)
        {
            for(int i=0;i<len;i++)
            {
                if((a[i]-'0')!=0)
                {
                    k=i;
                    break;
                }
            }
            t=a[0];a[0]=a[k];a[k]=t;
            if(strcmp(a,b)==0)
              cout<<"OK"<<endl;
            else
              cout<<"WRONG_ANSWER"<<endl;
        }
        return 0;          
    } 
  • 相关阅读:
    计算机基础
    如何增加一个IT产品的用户黏性
    计算机相关专业一门课程一个案例
    【2012年6月14日】中兴发布Grand(智观)N970
    bmp格式浅析
    3Dbook的使用
    中英文翻译格式
    软件学习书籍推荐
    WEB开发基础
    PHP学习
  • 原文地址:https://www.cnblogs.com/ylrwj/p/11014276.html
Copyright © 2011-2022 走看看