场景：socket 客户端将一个单向链表序列化后发送给服务端，服务端将之解析，重新构建单向链表。
Client.cpp
1 //遍历链表，填充到缓冲区 2 char* formatBuf(ListNode* p, char buf[100]) 3 { 4 ListNode* tmp = p; 5 //处理空链表 6 if (tmp == NULL) 7 { 8 std::cout << "空链表！" << std::endl; 9 } 10 memset(buf, 0, sizeof(buf)); 11 while (tmp->next != NULL) 12 { 13 tmp = tmp->next; 14 //填充到缓冲区 20 char tmpStr[25]; 21 sprintf(tmpStr, "%s/%s/%d ", tmp->Name, tmp->ID, tmp->Score); 22 strcat(buf, tmpStr); 23 } 24 return buf; 25 }
Server.cpp
1 //字符流解析 2 void parseStr(char* buf, int len) 3 { 4 //新建链表 5 ListNode *head, *node, *ptr; 6 head = (ListNode*)malloc(sizeof(ListNode)); 7 int i =0, count = 0; 8 char* p = buf;//offset ptr 9 ptr = head; 10 while(p < buf + len) 11 { 12 char name[5]; 13 char id[10]; 14 unsigned int s; 15 //字符串截取 16 sscanf(p, "%1s/%5s/%d", name, id, &s); 17 //printf("%s %s %d ", name, id, s); 18 //申请空间 19 node = (ListNode*)malloc(sizeof(ListNode)); 20 strcpy(node->Name, name); 21 strcpy(node->ID, id); 22 node->Score = s; 23 ptr->next = node; 24 node->next = NULL; 25 ptr = node; 26 27 p += 11;//指针偏移 28 } 29 printList(head); 30 }
参考资料
【1】https://ask.csdn.net/questions/370828 （二楼回答，我根据回答修改的）