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  • zoj 3195 Design the city lca倍增

    题目链接

    给一棵树, m个询问, 每个询问给出3个点, 求这三个点之间的最短距离。

    其实就是两两之间的最短距离加起来除2.

    倍增的lca模板

    #include <iostream>
    #include <vector>
    #include <cstdio>
    #include <cstring>
    #include <algorithm>
    #include <cmath>
    #include <map>
    #include <set>
    #include <string>
    #include <queue>
    #include <stack>
    #include <bitset>
    using namespace std;
    #define pb(x) push_back(x)
    #define ll long long
    #define mk(x, y) make_pair(x, y)
    #define lson l, m, rt<<1
    #define mem(a) memset(a, 0, sizeof(a))
    #define rson m+1, r, rt<<1|1
    #define mem1(a) memset(a, -1, sizeof(a))
    #define mem2(a) memset(a, 0x3f, sizeof(a))
    #define rep(i, n, a) for(int i = a; i<n; i++)
    #define fi first
    #define se second
    typedef pair<int, int> pll;
    const double PI = acos(-1.0);
    const double eps = 1e-8;
    const int mod = 1e9+7;
    const int inf = 1061109567;
    const int dir[][2] = { {-1, 0}, {1, 0}, {0, -1}, {0, 1} };
    const int maxn = 1e5+5;
    int head[maxn*2], num, dis[maxn], f[maxn], p[maxn][20], deep[maxn], n;
    struct node
    {
        int to, nextt, w;
    }e[maxn*2];
    void add(int u, int v, int w) {
        e[num].to = v, e[num].w = w, e[num].nextt = head[u], head[u] = num++;
    }
    void init() {
        num = 0;
        mem1(head);
        mem1(p);
    }
    void dfs(int u, int fa) {
        f[u] = fa;
        for(int i = head[u]; ~i; i = e[i].nextt) {
            int v = e[i].to;
            if(v == fa)
                continue;
            dis[v] = dis[u]+e[i].w;
            deep[v] = deep[u]+1;
            dfs(v, u);
        }
    }
    void lca_init()
    {
        int i,j;
        for(i = 1; i<=n; i++)
            p[i][0] = f[i];
        for(j = 1; (1<<j)<=n; j++) {
            for(i = 1; i<=n; i++) {
                if(p[i][j-1] != -1)
                    p[i][j] = p[p[i][j-1]][j-1];
            }
        }
    }
    int lca(int a,int b)
    {
        int i,j;
        if(deep[a]<deep[b])
            swap(a, b);
        for(i = 0; (1<<i)<=deep[a]; i++);
            i--;
        for(j = i; j>=0; j--)
            if(deep[a]-(1<<j)>=deep[b])
                a = p[a][j];
        if(a == b)
            return a;
        for(j = i; j>=0; j--)
        {
            if(p[a][j] != -1 && p[a][j] != p[b][j])
            {
                a = p[a][j];
                b = p[b][j];
            }
        }
        return f[a];
    }
    int main()
    {
        int x, y, m, w, z, ok = 0;
        while(cin>>n) {
            if(ok)
                puts("");
            ok = 1;
            init();
            for(int i = 0; i<n-1; i++) {
                scanf("%d%d%d", &x, &y, &w);
                add(x, y, w);
                add(y, x, w);
            }
            dfs(0, -1);
            lca_init();
            cin>>m;
            while(m--) {
                scanf("%d%d%d", &x, &y, &z);
                int ans = 0;
                ans += dis[x]+dis[y]-2*dis[lca(x,y)];
                ans += dis[x]+dis[z]-2*dis[lca(x,z)];
                ans += dis[y]+dis[z]-2*dis[lca(y,z)];
                printf("%d
    ", ans/2);
            }
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/yohaha/p/5094667.html
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