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  • 263. Ugly Number

    题目:

    Write a program to check whether a given number is an ugly number.

    Ugly numbers are positive numbers whose prime factors only include 2, 3, 5. For example, 6, 8 are ugly while 14 is not ugly since it includes another prime factor 7.

    Note that 1 is typically treated as an ugly number.

    链接: http://leetcode.com/problems/ugly-number/

    题解:

    验证丑数。数学题,我们直接除就好了。

    Time Compleixty - O(logn), Space Complexity - O(1).

    public class Solution {
        public boolean isUgly(int num) {
            if(num < 1) {
                return false;
            }
            while(num % 5 == 0) {
                num /= 5;
            }
            while(num % 3 == 0) {
                num /= 3;
            }   
            while(num % 2 == 0) {
                num /= 2;
            }
            
            return num == 1;
        }
    }

    二刷:

    Java:

    Time Compleixty - O(logn), Space Complexity - O(1).

    public class Solution {
        public boolean isUgly(int num) {
            if (num < 1) {
                return false;
            }
            while (num % 5 == 0) {
                num /= 5;
            }
            while (num % 3 == 0) {
                num /= 3;
            }
            while (num % 2 == 0) {
                num /= 2;
            }
            return num == 1;
        }
    }

    学习Stefan的写法

    public class Solution {
        public boolean isUgly(int num) {
           for (int i = 2; i < 6 && num != 0; i++) {
               while (num % i == 0) {
                   num /= i;
               }
           }
           return num == 1;
        }
    }

    三刷:

    Java:

    Time Compleixty - O(logn), Space Complexity - O(1).

    public class Solution {
        public boolean isUgly(int num) {
            if (num < 1) {
                return false;
            }
            while (num % 2 == 0) {
                num /= 2;
            }
            while (num % 3 == 0) {
                num /= 3;
            }
            while (num % 5 == 0) {
                num /= 5;
            }
            return num == 1;
        }
    }

    Reference:

    https://leetcode.com/discuss/52703/2-4-lines-every-language

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  • 原文地址:https://www.cnblogs.com/yrbbest/p/5018930.html
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