You are climbing a stair case. It takes n steps to reach to the top.
Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?
class Solution { public: int climbStairs(int n) { if(n==1) return 1; if(n==2) return 2; return climbStairs(n-1)+climbStairs(n-2); } };
用递归,显示运行超时。(很多运算重复了)
class Solution { public: int climbStairs(int n) { if(n<=2) return n; int st[n]; st[0]=1; st[1]=2; int i; for(i=2;i<n;i++) { st[i]=st[i-1]+st[i-2]; } return st[n-1]; } };
用数组保存,节省堆栈资源