bzoj 1391 [Ceoi2008]order

有N个工作，M种机器，每种机器你可以租或者买过来. 每个工作包括若干道工序，每道工序需要某种机器来完成,你可以通过购买或租用机器来完成。现在给出这些参数，求最大利润

第一行给出 N,M(1<=N<=1200,1<=M<=1200) 下面将有N块数据，每块数据第一行给出完成这个任务能赚到的钱(其在[1,5000])及有多少道工序接下来若干行每行两个数，分别描述完成工序所需要的机器编号及租用它的费用(其在[1,20000]) 最后M行，每行给出购买机器的费用(其在[1,20000])

最大利润

2 3
100 2
1 30
2 20
100 2
1 40
3 80
50
80
110

50

　　有点类似于最大权闭合子图。任务和源点连边，容量为获利，任务和完成它的工序所用机器连边，容量为租用费用，机器和汇点连边，容量为它的价格。答案是总获利 - 最大流。

　　这些都还好。。最坑的是，我的模板在前几道题上正常运行，这道题用vectot炸掉了，一直鬼畜地Runtime Error，我也表示很绝望，换成数组才能Accepted。

Code

  1 /**
  2  * bzoj
  3  * Problem#1391
  4  * Accepted
  5  * Time:4860ms
  6  * Memory:46372k
  7  */
  8 #include <iostream>
  9 #include <cstdio>
 10 #include <ctime>
 11 #include <cmath>
 12 #include <cctype>
 13 #include <cstring>
 14 #include <cstdlib>
 15 #include <fstream>
 16 #include <sstream>
 17 #include <algorithm>
 18 #include <map>
 19 #include <set>
 20 #include <stack>
 21 #include <queue>
 22 #include <vector>
 23 #include <stack>
 24 #ifndef WIN32
 25 #define Auto "%lld"
 26 #else
 27 #define Auto "%I64d"
 28 #endif
 29 using namespace std;
 30 typedef bool boolean;
 31 const signed int inf = (signed)((1u << 31) - 1);
 32 const int eps = 1e-6;
 33 #define smin(a, b) a = min(a, b)
 34 #define smax(a, b) a = max(a, b)
 35 #define max3(a, b, c) max(a, max(b, c))
 36 #define min3(a, b, c) min(a, min(b, c))
 37 template<typename T>
 38 inline boolean readInteger(T& u){
 39     char x;
 40     int aFlag = 1;
 41     while(!isdigit((x = getchar())) && x != '-' && x != -1);
 42     if(x == -1) {
 43         ungetc(x, stdin);    
 44         return false;
 45     }
 46     if(x == '-'){
 47         x = getchar();
 48         aFlag = -1;
 49     }
 50     for(u = x - '0'; isdigit((x = getchar())); u = (u << 1) + (u << 3) + x - '0');
 51     ungetc(x, stdin);
 52     u *= aFlag;
 53     return true;
 54 }
 55 
 56 typedef class Edge {
 57     public:
 58         int end;
 59         int next;
 60         int flow;
 61         int cap;
 62         Edge(int end = 0, int next = -1, int flow = 0, int cap = 0):end(end), next(next), flow(flow), cap(cap) {    }
 63 }Edge;
 64 
 65 typedef class MapManager {
 66     public:
 67         int ce;
 68         Edge* edge;
 69         int* h;
 70         
 71         MapManager():ce(0), h(NULL) {        }
 72         MapManager(int nodes, int limit):ce(0) {
 73             h = new int[(const int)(nodes + 1)];
 74             edge = new Edge[(const int)(limit + 1)];
 75             memset(h, -1, sizeof(int) * (nodes + 1));
 76         }
 77         
 78         inline void addEdge(int from, int end, int flow, int cap) {
 79             edge[ce] = (Edge(end, h[from], flow, cap));
 80             h[from] = ce++;
 81         }
 82         
 83         inline void addDoubleEdge(int from, int end, int cap) {
 84             addEdge(from, end, 0, cap);
 85             addEdge(end, from, cap, cap);
 86         }
 87         
 88         Edge& operator [] (int pos) {
 89             return edge[pos];
 90         }
 91 }MapManager;
 92 #define m_begin(g, i) (g).h[(i)]
 93 #define m_endpos -1
 94 
 95 int n, m;
 96 MapManager g;
 97 int s, t;
 98 int sum = 0;
 99 
100 inline void init() {
101     readInteger(n);
102     readInteger(m);
103     g = MapManager(n + m + 3, (n + 1) * (m + 1) * 2);
104     s = 0, t = n + m + 1;
105     for(int i = 1, a, b; i <= n; i++) {
106         readInteger(a);
107         readInteger(b);
108         g.addDoubleEdge(s, i, a);
109         sum += a;
110         for(int j = 1, c, d; j <= b; j++) {
111             readInteger(c);
112             readInteger(d);
113             g.addDoubleEdge(i, c + n, d);
114         }
115     }
116     for(int i = 1, a; i <= m; i++) {
117         readInteger(a);
118         g.addDoubleEdge(i + n, t, a);
119     }
120 }
121 
122 int* dis;
123 boolean* vis;
124 queue<int> que;
125 inline boolean bfs() {
126     memset(vis, false, sizeof(boolean) * (t + 2));
127     que.push(s);
128     vis[s] = true;
129     dis[s] = 0;
130     while(!que.empty()) {
131         int e = que.front();
132         que.pop();
133         for(int i = m_begin(g, e); i != m_endpos; i = g[i].next) {
134             if(g[i].cap == g[i].flow)    continue;
135             int eu = g[i].end;
136             if(vis[eu])    continue;
137             vis[eu] = true;
138             dis[eu] = dis[e] + 1;
139             que.push(eu);
140         }
141     }
142     return vis[t];
143 }
144 
145 int *cur;
146 inline int blockedflow(int node, int minf) {
147     if((node == t) || (minf == 0))    return minf;
148     int f, flow = 0;
149     for(int& i = cur[node]; i != m_endpos; i = g[i].next) {
150         int& eu = g[i].end;
151         if(dis[eu] == (dis[node] + 1) && (f = blockedflow(eu, min(minf, g[i].cap - g[i].flow))) > 0) {
152             minf -= f;
153             flow += f;
154             g[i].flow += f;
155             g[i ^ 1].flow -= f;
156             if(minf == 0)    return flow;
157         }
158     }
159     return flow;
160 }
161 
162 inline void init_dinic() {
163     vis = new boolean[(const int)(t + 3)];
164     dis = new int[(const int)(t + 3)];
165     cur = new int[(const int)(t + 3)];
166 }
167 
168 inline int dinic() {
169     int maxflow = 0;
170     while(bfs()) {
171         for(int i = s; i <= t; i++)
172             cur[i] = m_begin(g, i);
173         maxflow += blockedflow(s, inf);
174     }
175     return maxflow;
176 } 
177 
178 inline void solve() {
179     printf("%d
", sum - dinic());
180 }
181 
182 int main() {
183 //    freopen("order.in", "r", stdin);
184     init();
185     init_dinic();
186     solve();
187     return 0;
188 }

bzoj 1391 [Ceoi2008]order

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