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  • s5_day9作业

    # 1 编写 tail -f a.txt |grep 'error' |grep '404'命令,周一默写
    # import time
    # def tail(filepath,encoding='utf-8'):
    #     with open(filepath,encoding=encoding)as f:
    #         f.seek(0,2)
    #         while True:
    #             line=f.readline()
    #             if line:
    #                 yield line
    #             else:
    #                 time.sleep(0.5)
    # def grep(lines,pattern):
    #     for line in lines:
    #         if pattern in line:
    #             # print(line)
    #             yield line
    # g=tail('a.txt')
    # g2=grep(g,'error')
    # g3=grep(g2,'404')
    # for i in g3:
    #     print(i)
    # 2 文件a.txt内容
    # apple 10 3
    # tesla 100000 1
    # mac 3000 2
    # lenovo 30000 3
    # chicken 10 3
    # with open('a.txt','w',encoding='utf-8')as f:
    #     f.write('apple 10 3
    tesla 100000 1
    mac 3000 2
    lenovo 30000 3
    chicken 10 3')
    # 要求使用列表解析,从文件a.txt中取出每一行,做成下述格式
    # [{‘name’:'apple','price':10,'count':3},{...},{...},...]
    # with open('a.txt', 'r', encoding='utf-8')as f:
        # print([{'name':line.strip().split()[0],'price':line.strip().split()[1],'count':line.strip().split()[2]} for line in f])
        # for i in [{'name':line.strip().split()[0],'price':line.strip().split()[1],'count':line.strip().split()[2]} for line in f]:
        #     print(i)
    # 3 格式与2一样,但只保留价格大于1000的商品信息
    # with open('a.txt',encoding='utf-8')as f:
    #     for i in [{'name':line.strip().split()[0],'price':line.strip().split()[1],'count':line.strip().split()[2]} for line in f]:
    #         if int(i['price'])>1000:
    #             print(i)
    # 4 周末大作业(见图):
    #     只实现作业要求的查询功能
    #     增加,删除,修改功能为选做题
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  • 原文地址:https://www.cnblogs.com/z-x-y/p/7086892.html
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