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  • UVA 220 Othello

    题目链接:https://vjudge.net/problem/UVA-220

    题目翻译摘自《算法禁赛入门经典》

    题目大意

      你的任务是模拟黑白棋游戏的进程。

      有 3 种指令:

    1. L指令:打印所有合法操作,按照从上到下,从左到右的顺序排列(没有合法操作时输出 No legal move)。
    2. M指令:放一枚棋子在 (x, y)。如果当前游戏者没有合法操作,则是先切换游戏者再操作。输入保证这个操作是合法的。输出操作完毕后黑白方的棋子总数。
    3. Q指令:退出游戏,并打印当前棋盘(格式同输入)。

    分析

      略。

    代码如下

      1 #include <bits/stdc++.h>
      2 using namespace std;
      3  
      4 #define INIT() ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
      5 #define Rep(i,n) for (int i = 0; i < (n); ++i)
      6 #define For(i,s,t) for (int i = (s); i <= (t); ++i)
      7 #define rFor(i,t,s) for (int i = (t); i >= (s); --i)
      8 #define ForLL(i, s, t) for (LL i = LL(s); i <= LL(t); ++i)
      9 #define rForLL(i, t, s) for (LL i = LL(t); i >= LL(s); --i)
     10 #define foreach(i,c) for (__typeof(c.begin()) i = c.begin(); i != c.end(); ++i)
     11 #define rforeach(i,c) for (__typeof(c.rbegin()) i = c.rbegin(); i != c.rend(); ++i)
     12  
     13 #define pr(x) cout << #x << " = " << x << "  "
     14 #define prln(x) cout << #x << " = " << x << endl
     15  
     16 #define LOWBIT(x) ((x)&(-x))
     17  
     18 #define ALL(x) x.begin(),x.end()
     19 #define INS(x) inserter(x,x.begin())
     20  
     21 #define ms0(a) memset(a,0,sizeof(a))
     22 #define msI(a) memset(a,inf,sizeof(a))
     23 #define msM(a) memset(a,-1,sizeof(a))
     24 
     25 #define MP make_pair
     26 #define PB push_back
     27 #define ft first
     28 #define sd second
     29  
     30 template<typename T1, typename T2>
     31 istream &operator>>(istream &in, pair<T1, T2> &p) {
     32     in >> p.first >> p.second;
     33     return in;
     34 }
     35  
     36 template<typename T>
     37 istream &operator>>(istream &in, vector<T> &v) {
     38     for (auto &x: v)
     39         in >> x;
     40     return in;
     41 }
     42  
     43 template<typename T1, typename T2>
     44 ostream &operator<<(ostream &out, const std::pair<T1, T2> &p) {
     45     out << "[" << p.first << ", " << p.second << "]" << "
    ";
     46     return out;
     47 }
     48 
     49 inline int gc(){
     50     static const int BUF = 1e7;
     51     static char buf[BUF], *bg = buf + BUF, *ed = bg;
     52     
     53     if(bg == ed) fread(bg = buf, 1, BUF, stdin);
     54     return *bg++;
     55 } 
     56 
     57 inline int ri(){
     58     int x = 0, f = 1, c = gc();
     59     for(; c<48||c>57; f = c=='-'?-1:f, c=gc());
     60     for(; c>47&&c<58; x = x*10 + c - 48, c=gc());
     61     return x*f;
     62 }
     63 
     64 template<class T>
     65 inline string toString(T x) {
     66     ostringstream sout;
     67     sout << x;
     68     return sout.str();
     69 }
     70  
     71 typedef long long LL;
     72 typedef unsigned long long uLL;
     73 typedef pair< double, double > PDD;
     74 typedef pair< int, int > PII;
     75 typedef pair< int, PII > PIPII;
     76 typedef pair< string, int > PSI;
     77 typedef pair< int, PSI > PIPSI;
     78 typedef set< int > SI;
     79 typedef set< PII > SPII;
     80 typedef vector< int > VI;
     81 typedef vector< VI > VVI;
     82 typedef vector< PII > VPII;
     83 typedef map< int, int > MII;
     84 typedef map< int, string > MIS;
     85 typedef map< int, PII > MIPII;
     86 typedef map< PII, int > MPIII;
     87 typedef map< string, int > MSI;
     88 typedef map< string, string > MSS;
     89 typedef map< PII, string > MPIIS;
     90 typedef map< PII, PII > MPIIPII;
     91 typedef multimap< int, int > MMII;
     92 typedef multimap< string, int > MMSI;
     93 //typedef unordered_map< int, int > uMII;
     94 typedef pair< LL, LL > PLL;
     95 typedef vector< LL > VL;
     96 typedef vector< VL > VVL;
     97 typedef priority_queue< int > PQIMax;
     98 typedef priority_queue< int, VI, greater< int > > PQIMin;
     99 const double EPS = 1e-6;
    100 const LL inf = 0x7fffffff;
    101 const LL infLL = 0x7fffffffffffffffLL;
    102 const LL mod = 1e9 + 7;
    103 const int maxN = 1e4 + 7;
    104 const LL ONE = 1;
    105 const LL evenBits = 0xaaaaaaaaaaaaaaaa;
    106 const LL oddBits = 0x5555555555555555;
    107 
    108 struct Point{
    109     int X, Y;
    110     
    111     Point() {}
    112     Point(int x, int y) : X(x), Y(y) {}
    113     
    114     bool operator< (const Point &x) const {
    115         if(X == x.X) return Y < x.Y;
    116         return X < x.X;
    117     }
    118 };
    119 
    120 ostream &operator<< (ostream &out, const Point &x) {
    121     out << "(" << x.X << "," << x.Y << ")";
    122     return out;
    123 }
    124 
    125 int T, board[10][10], cur;
    126 PII dir[] = {MP(0, -1), MP(-1, -1), MP(-1, 0), MP(-1, 1), MP(0, 1), MP(1, 1), MP(1, 0), MP(1, -1)};
    127 
    128 char nextchar() {
    129     char ret;
    130     while(ret = getchar()) if(ret != '
    ' && ret != '
    ') break;
    131     return ret;
    132 }
    133 
    134 void list_move() {
    135     set< Point > sp;
    136     int nxtcur = (cur == 'W') ? 'B' : 'W';
    137     
    138     For(x, 1, 8) {
    139         For(y, 1, 8) {
    140             if(board[x][y] != cur) continue;
    141             Rep(i, 8) {
    142                 int k = 1;
    143                 int a = x + dir[i].ft, b = y + dir[i].sd;
    144                 while(a > 0 && a < 9 && b > 0 && b < 9 && board[a][b] == nxtcur) {
    145                     ++k;
    146                     a += dir[i].ft;
    147                     b += dir[i].sd;
    148                 }
    149                 if(k > 1 && board[a][b] == '-') sp.insert(Point(a, b));
    150             }
    151         }
    152     }
    153     
    154     if(sp.empty()) { // 如果没有合法输入要交换选手 
    155         printf("No legal move.
    ");
    156         cur = nxtcur;
    157     }
    158     else {
    159         foreach(i, sp) {
    160             if(i != sp.begin()) cout << " "; 
    161             cout << *i;
    162         }
    163         cout << endl;
    164     }
    165 }
    166 
    167 void move(int x, int y) {
    168     int nxtcur = (cur == 'W') ? 'B' : 'W';
    169     bool flag = false;
    170     
    171     Rep(i, 8) { // 每个方向都看看 
    172         int k = 1;
    173         int a = x + dir[i].ft, b = y + dir[i].sd;
    174         while(a > 0 && a < 9 && b > 0 && b < 9 && board[a][b] == nxtcur) {
    175             ++k;
    176             a += dir[i].ft;
    177             b += dir[i].sd;
    178         }
    179         if(board[a][b] == cur) {
    180             For(j, 1, k - 1) {
    181                 flag = true;
    182                 a = x + j * dir[i].ft;
    183                 b = y + j * dir[i].sd;
    184                 board[a][b] = cur;
    185             }
    186         }
    187     }
    188     
    189     if(flag) board[x][y] = cur; // 可能是非法移动 
    190     else {
    191         cur = nxtcur;
    192         move(x, y);
    193         return;
    194     } 
    195     
    196     int cntB = 0, cntW = 0;
    197     For(i, 1, 8) {
    198         For(j, 1, 8) {
    199             if(board[i][j] == 'B') ++cntB;
    200             if(board[i][j] == 'W') ++cntW;
    201         }
    202     }
    203     
    204     printf("Black -%3d White -%3d
    ", cntB, cntW);
    205     cur = nxtcur;
    206 }
    207 
    208 void display_board() {
    209     For(i, 1, 8) {
    210         For(j, 1, 8) cout << (char)board[i][j];
    211         cout << endl;
    212     }
    213 }
    214 
    215 int main(){
    216     //freopen("MyOutput.txt","w",stdout);
    217     //freopen("input.txt","r",stdin);
    218     //INIT();
    219     char op;
    220     cin >> T;
    221     Rep(i, T) {
    222         ms0(board);
    223         For(i, 1, 8) For(j, 1, 8) board[i][j] = nextchar();
    224         
    225         if(i) printf("
    ");
    226         cur = nextchar();
    227         while(op = nextchar()) {
    228             if(op == 'L') list_move();
    229             if(op == 'M') {
    230                 int x = nextchar() - '0';
    231                 int y = nextchar() - '0';
    232                 move(x, y);
    233             }
    234             if(op == 'Q') {
    235                 display_board();
    236                 break;
    237             }
    238         }
    239     }
    240     return 0;
    241 }
    View Code
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  • 原文地址:https://www.cnblogs.com/zaq19970105/p/11033237.html
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