16进制a+b

Description

Many classmates said to me that A+B is must needs. If you can’t AC this problem, you would invite me for night meal. ^_^

Input

Input may contain multiple test cases. Each case contains A and B in one line. A, B are hexadecimal number. Input terminates by EOF.

Output

Output A+B in decimal number in one line.

Sample Input

1 9
A B
a b

Sample Output

10
21
21

注意：不只是单个的字符 有可能是2个甚至多个 所以要用字符串输入

AC代码：

#include <stdio.h>
#include <string.h>
int main()
{
    char a[100],b[100];
    int c=0,d=0,i;
    while(scanf("%s %s",a,b)!=EOF)
    {
        int n=strlen(a);
        int m=strlen(b);
        int p=1;
        for(i=n-1;i>=0;i--)
        {
            if(a[i]>='a'&&a[i]<='z')
                c+=(a[i]-87)*p;
            else
            if(a[i]>='A'&&a[i]<='Z')
              c+=(a[i]-55)*p;
            else
            if(a[i]>='0'&&a[i]<='9')
              c+=(a[i]-48)*p;
            p*=16;
        }
        p=1;
        for(i=m-1;i>=0;i--)
        {
            if(b[i]>='a'&&b[i]<='z')
                d+=(b[i]-87)*p;
            else
            if(b[i]>='A'&&b[i]<='Z')
              d+=(b[i]-55)*p;
            else
            if(b[i]>='0'&&b[i]<='9')
              d+=(b[i]-48)*p;
            p*=16;
        }
        printf("%d
",c+d);
        c=0,d=0;
        memset(a,'0',sizeof(a));
        memset(b,'0',sizeof(b));
    }
    return 0;
}

还有一种简单做法：

#include <stdio.h>
#include <string.h>
int main()
{
    int a,b;
    while(scanf("%x %x",&a,&b)!=EOF)
    {
        printf("%d
",a+b);

    }
}