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  • 孩子: DEV C++ 高精度 减法

    #include<bits/stdc++.h>
    using namespace std;
    int a[1005]={0},b[1005]={0},c[1005]={0};
    string st1,st2;
    int main(){
    cin>>st1>>st2;
    int len1=st1.size();
    int len2=st2.size();
    int fh=0,l,zh=0,k=0;
    //cout<<st1<<endl<<st2<<endl;
    if(len1<len2)
    {
    l=len2;
    fh=1;
    //swap(st1,st2);

    //swap(len1,len2);
    }
    else
    {

    if(len1>len2)
    {
    l=len1;
    fh=0;
    }
    else
    {
    if(st1<st2)
    {
    l=len2;
    fh=1;
    //swap(st1,st2);
    //swap(len1,len2);
    //cout<<fh<<endl;
    }
    else
    {
    l=len1;
    fh=0;

    }
    }

    }

    if(fh!=0)
    {
    swap(st1,st2);
    swap(len1,len2);
    }

    reverse(st1.begin(),st1.end());
    reverse(st2.begin(),st2.end());
    //cout<<st1<<endl<<st2<<endl;
    for(int i=0;i<len1;i++)
    {
    b[i]=st1[i]-'0';
    //cout<<b[i]<<" b:"<<len1<<endl;
    }
    //cout<<len1<<endl;
    for(int i=0;i<len2;i++)
    {
    c[i]=st2[i]-'0';
    // cout<<c[i]<<" C:"<<len2<<endl;
    }
    //cout<<len2<<endl;

    for(int i=0;i<l;i++)
    {
    //cout<<b[i]<<"-"<<c[i]<<"=";
    a[i]=b[i]-c[i];
    //cout<<a[i]<<endl;
    if(a[i]<0)
    {
    b[i+1]--;
    b[i]=b[i]+10;
    i--;
    }

    }
    //cout<<endl;
    if(fh!=0)
    cout<<'-';
    for(int i=l-1;i>=0;i--)
    {

    zh=zh+a[i];
    }

    //cout<<"l:"<<l<<"zh:"<<zh<<endl;

    for(int i=l-1;i>=0;i--)
    {
    if(zh!=0)
    {
    if(a[i]!=0 || k==1)
    {
    cout<<a[i];
    k=1;
    }
    else
    {
    }
    }
    }
    if(zh==0)
    cout<<"0";
    return 0;
    }

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  • 原文地址:https://www.cnblogs.com/zdc-shine/p/11324113.html
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