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  • [线段树] [洛谷] P1531 I Hate It

    线段树的区间查询和单点更新

    复习敲一下

    //#pragma GCC optimize(2)
    #include <cstdio>
    #include <iostream>
    #include <cstdlib>
    #include <cmath>
    #include <cctype>
    #include <string>
    #include <cstring>
    #include <algorithm>
    #include <stack>
    #include <queue>
    #include <set>
    #include <map>
    #include <ctime>
    #include <vector>
    #include <fstream>
    #include <list>
    #include <iomanip>
    #include <numeric>
    using namespace std;
    typedef long long ll;
    
    const int MAXN = 1e6 + 10;
    
    int arr[MAXN] ;
    
    int tree[MAXN];
    
    int N, M;
    
    void init(int now, int l, int r)
    {
        if(l == r)
        {
        	tree[now] = arr[l];
        	return ;
    	}
    
        int mid = l + (r - l) / 2;
    
        init(now * 2, l, mid);
    	
    	init(now * 2 + 1, mid + 1, r);
    
        tree[now] = max(tree[now * 2], tree[now * 2 + 1]);
    
    }
    
    void change(int now, int l, int r, int find, int key)
    {
    	if(r < find || l > find)
    		return ;
    	if(l == r)
    	{
    		if(tree[now] < key)
    			tree[now] = key;
    		return ;
    	}
    	
    	int mid = l + (r - l) / 2;
    	
    	change(now * 2, l, mid, find, key);
    	
    	change(now * 2 + 1, mid + 1, r, find, key);
    	
    	tree[now] = max(tree[now * 2], tree[now * 2 + 1]);
    }
    
    int qury(int now, int l, int r, int x, int y)
    {
    	if(l > y || r < x)
    		return 0;
    	if(x <= l && y >= r)
    	{
    		return tree[now];
    	}
    	
    	int ans = 0;
    	
    	int mid = l + (r - l) / 2;
    	
    	ans = max(ans, qury(now * 2, l, mid, x, y) );
    	
    	ans = max(ans, qury(now * 2 + 1, mid + 1, r, x, y) );
    	
    	return ans;
    }
    
    int main()
    {
        ios::sync_with_stdio(false);
    
        cin.tie(0);     cout.tie(0);
    
        cin>>N>>M;
    
        for(int i = 1; i <= N; i++)
            cin>>arr[i];
    
        init(1, 1, N);
    
        while(M--)
        {
        	char oprt;
        	
        	int x, y;
        	
        	cin>>oprt>>x>>y;
        	
        	if(oprt == 'Q')
        	{
        		cout<<qury(1, 1, N, x, y)<<endl;
        		
    		}
        	
        	else
        	{
        		change(1, 1, N, x, y);
    		}
    	}
    
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/zeolim/p/12270472.html
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