南阳热省赛A——找规律——Googol String

仔细观察就会发现K = pow(2, m) + pow(2, m-1) 数要翻转一次

/************************************************
* Author        :Powatr
* Created Time  :2015/10/20 18:06:07
* File Name     :A.cpp
 ************************************************/

#include <cstdio>
#include <algorithm>
#include <iostream>
#include <sstream>
#include <cstring>
#include <cmath>
#include <string>
#include <vector>
#include <queue>
#include <deque>
#include <stack>
#include <list>
#include <map>
#include <set>
#include <bitset>
#include <cstdlib>
#include <ctime>
using namespace std;

#define lson l, mid, rt << 1
#define rson mid + 1, r, rt << 1 | 1
typedef long long ll;
const int MAXN = 1e5 + 10;
const int INF = 0x3f3f3f3f;
const int MOD = 1e9 + 7;

long long Pow(int n)
{
    long long res = 1;
    for(int i = 1; i <= n; i++)
        res *= 2;
    return res;
}

int solve(long long k)
{
    int cout1 = 0;
    while(1){
    int m = log(k) / log(2);
      if(Pow(m) + Pow(m-1) == k){
        cout1++;
        k -= Pow(m);
       }
      else k -= Pow(m);
      if(k == 1||k == 0) break;
    }
    if(cout1 % 2 == 1) return 1;
    return 0;
}

int main(){
    int T;
    long long k;
    scanf("%d", &T);
    for(int cas = 1; cas <= T; cas++){
           scanf("%lld", &k);
           printf("Case #%d: ", cas);
           int ans = solve(k);
           printf("%d
", ans);
    }
    return 0;
}