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  • 第几天? 2005

    原题:http://acm.hdu.edu.cn/showproblem.php?pid=2005
    #include <stdio.h>
    
    int main()
    {
    	int year,dd,mm;
    	int sum=0;
    	while(scanf("%d/%d/%d",&year,&mm,&dd)!=EOF)
    	{
    		switch(mm)
    		{
    		case 1:
    			sum=dd;
    			break;
    		case 2:
    			sum=31+dd;
    			break;
    		case 3:
    			sum=31+28+dd;
    			break;
    		case 4:
    			sum=31+28+31+dd;
    			break;
    		case 5:
    			sum=31+28+31+30+dd;
    			break;
    		case 6:
    			sum=31+28+31+30+31+dd;
    			break;
    		case 7:
    			sum=31+28+31+30+31+30+dd;
    			break;
    		case 8:
    			sum=31+28+31+30+31+30+31+dd;
    			break;
    		case 9:
    			sum=31+28+31+30+31+30+31+31+dd;
    			break;
    		case 10:
    			sum=31+28+31+30+31+30+31+31+30+dd;
    			break;
    		case 11:
    			sum=31+28+31+30+31+30+31+31+30+31+dd;
    			break;
    		case 12:
    			sum=31+28+31+30+31+30+31+31+30+31+30+dd;
    			break;
            default:
    			printf("您输入的月份有误,请重新输入!\n");
    		}
    		if((mm>2)&&((year%400)==0||(year%4==0&&year%100!=0)))  //能被400整除或者被4整除不能被100整除的是闰年 月份要大于2
    		{ 
    			sum+=1;
    		}
    		printf("%d\n",sum);
    	}
    	
    	return 0;
    }
    
      ========================================================
    
    #include <stdio.h>
    
    int main()
    {
    	int yy,dd,mm,sum;
    	int a[12]={31,28,31,30,31,30,31,31,30,31,30,31};
    	while(scanf("%d/%d/%d",&yy,&mm,&dd)!=EOF)
    	{
            sum=0;
    		for(int i=0;i<mm-1;i++)
    		{
    			sum+=a[i];	//求前几个月的日子之和
    		}
    		sum+=dd;	//加上本月的天数
    		if(mm>2&&(yy%400==0||(yy%4==0&&yy%100!=0)))
    		{
    			sum++;
    		}
    		printf("%d\n",sum);
    	}
    	return 0;
    }
    

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  • 原文地址:https://www.cnblogs.com/zerocc/p/1915657.html
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