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  • 三级菜单 ,求1

    1.猜年龄游戏:

    要求:

        允许用户最多尝试3次
        每尝试3次后,如果还没猜对,就问用户是否还想继续玩,如果回答Y或y, 就继续让其猜3次,以此往复,如果回答N或n,就退出程序
        如果猜对了,有三次选择奖励的机会,不要奖励可以随时退出,并打印奖品清单给用户看;
    count = 0
    real_age = 19
    goods_list = [
        '芭比娃娃',
        '变形金刚',
        '小猪佩奇',
        '蜘蛛侠',
        '模型飞机',
        'inflatable doll'
    ]
    customer_goods_list = []
    
    while True:
        age = input('请猜一下真实年龄(q退出)>>>:').strip().lower()
        if age == 'q': break
        if not age.isdigit():
            print('请输入纯数字!')
            continue
        age = int(age)
        if age == real_age:
            print('恭喜你!猜对了!你有3次选择奖励的机会!','
    ')
            choice_count = 0
            while True:
                for index, good in enumerate(goods_list, 1):
                    print(index, good)
                choice = input('请选择奖品(或者直接按q退出)>>>:').strip().lower()
                if choice == 'q': break
                if not choice.isdigit():
                    print('请输入数字!')
                    continue
                choice = int(choice) - 1
                if choice not in range(len(goods_list)):
                    print('选择的奖品不在范围内,请重新输入!')
                    continue
                else:
                    choice_count += 1
                    print(f'你选择的奖品是:{goods_list[choice]},还有{3-choice_count}次机会!')
                    customer_goods_list.append(goods_list[choice])
    
                if choice_count == 3: break
            print(f'你的奖品清单:{customer_goods_list}')
            break
    
        elif age > real_age:
            print('猜大了!')
            continue
        else:
            print('猜小了!')
        count += 1
        if count == 3:
            while True:
                again_choice = input('还要再玩三次吗?输y再玩3次,或者输n直接退出>>>:').strip().lower()
                if again_choice == 'y':
                    count = 0
                    continue
                elif again_choice == 'n':
                    exit()
                    #quit()
                else:
                    print('输入不正确,请重试!')
     
    View Code

    2.三级菜单:

    1. 打印省、市、县三级菜单

    2. 可返回上一级

    3. 可随时退出程序

    menu = {
        '北京': {
            '海淀': {
                '五道口': {
                    'soho': {},
                    '网易': {},
                    'google': {}
                },
                '中关村': {
                    '爱奇艺': {},
                    '汽车之家': {},
                    'youku': {},
                },
                '上地': {
                    '百度': {},
                },
            },
            '昌平': {
                '沙河': {
                    '老男孩': {},
                    '北航': {},
                },
                '天通苑': {},
                '回龙观': {},
            },
            '朝阳': {},
            '东城': {},
        },
        '上海': {
            '闵行': {
                "人民广场": {
                    '炸鸡店': {}
                }
            },
            '闸北': {
                '火车战': {
                    '携程': {}
                }
            },
            '浦东': {},
        },
        '山东': {},
    }
    layers = [menu, ]
    while True:
        if len(layers) == 0: break
        current_layers = layers[-1]
        # print(current_layers,type(current_layers),'=================')
        for key in current_layers:
            print(key)
        choice = input('请选择(b返回上一层,q直接退出)>>>:').strip()
        if choice == 'b':
            layers.pop(-1)
            # print(layers,'+++++++++++++++++')
            continue
        if choice == 'q': break
        if choice not in current_layers:
            continue
        else:
            layers.append(current_layers[choice])
            # for i in layers:
            #     print(i,'@@@@@@@@@@@@@@@@@@@@')
            # print(layers,'-------------------------',len(layers))
            # print(current_layers[choice],type(current_layers[choice]),'**********************')
    View Code
    3.求1 - 2 + 3 - 4 + 5...99的所有数的和
    # 求1 - 2 + 3 - 4 + 5...99的所有数的和
    
    # 方法1
    count = 0
    get_sum = 0
    while True:
        if count == 100:
            break
        get_sum += count * ((-1) ** (count + 1))
        count += 1
    print(get_sum)
    
    # 方法2
    count = 0
    get_sum = 0
    get_sum1 = 0
    get_sum2 = 0
    while True:
        if count == 100:
            break
        if count % 2 == 0:
            get_sum1 -= count
        else:
            get_sum2 += count
        get_sum = get_sum1 + get_sum2
        count += 1
    print(get_sum)
    View Code

     

     

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  • 原文地址:https://www.cnblogs.com/zhangchaocoming/p/11520208.html
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