zoukankan      html  css  js  c++  java
  • codeforces 569B B. Inventory(水题)

    题目链接:

    B. Inventory

    time limit per test
    1 second
    memory limit per test
    256 megabytes
    input
    standard input
    output
    standard output

    Companies always have a lot of equipment, furniture and other things. All of them should be tracked. To do this, there is an inventory number assigned with each item. It is much easier to create a database by using those numbers and keep the track of everything.

    During an audit, you were surprised to find out that the items are not numbered sequentially, and some items even share the same inventory number! There is an urgent need to fix it. You have chosen to make the numbers of the items sequential, starting with 1. Changing a number is quite a time-consuming process, and you would like to make maximum use of the current numbering.

    You have been given information on current inventory numbers for n items in the company. Renumber items so that their inventory numbers form a permutation of numbers from 1 to n by changing the number of as few items as possible. Let us remind you that a set of n numbers forms a permutation if all the numbers are in the range from 1 to n, and no two numbers are equal.

    Input

    The first line contains a single integer n — the number of items (1 ≤ n ≤ 10^5).

    The second line contains n numbers a1, a2, ..., an (1 ≤ ai ≤ 10^5) — the initial inventory numbers of the items.

    Output

    Print n numbers — the final inventory numbers of the items in the order they occur in the input. If there are multiple possible answers, you may print any of them.

    Examples
    input
    3
    1 3 2
    output
    1 3 2 
    input
    4
    2 2 3 3
    output
    2 1 3 4 
    input
    1
    2
    output
    1 
    Note

    In the first test the numeration is already a permutation, so there is no need to change anything.

    In the second test there are two pairs of equal numbers, in each pair you need to replace one number.

    In the third test you need to replace 2 by 1, as the numbering should start from one.

    题意:

    把n个数变成1到n这n个数输出,就是把原来重复的和大于n的去掉,补上1到n中没有出现过的;

    思路:

    水题,直接不想说;

    AC代码:

    /*2014300227    569B - 26    GNU C++11    Accepted    46 ms    1196 KB*/
    #include <bits/stdc++.h>
    using namespace std;
    const int N=1e5+4;
    typedef long long ll;
    const double PI=acos(-1.0);
    int n,a[N],vis[N];
    queue<int>qu;
    int main()
    {
        scanf("%d",&n);
        for(int i=1;i<=n;i++)
        {
            scanf("%d",&a[i]);
            vis[a[i]]++;
        }
        for(int i=1;i<=n;i++)
        {
            if(!vis[i])qu.push(i);
        }
        for(int i=1;i<=n;i++)
        {
            if(a[i]>n)printf("%d ",qu.front()),qu.pop();
            else {
            if(vis[a[i]]==1)printf("%d ",a[i]);
            else if(vis[a[i]]>1)
            {
                printf("%d ",qu.front());
                qu.pop();
                vis[a[i]]--;
            }
            }
        }
    
        return 0;
    }
  • 相关阅读:
    validation 参数效验框架
    小酌一下:Maven
    小酌一下:git 常用命令
    小酌一下:anaconda 基本操作
    小酌一下:Win10 解决fetch_20newsgroups下载速度巨慢
    学习笔记:Python3 异常处理
    学习笔记:Python3 面向对象
    学习笔记:Python3 函数式编程
    学习笔记:Python3 函数
    学习笔记:Python3 高级特性
  • 原文地址:https://www.cnblogs.com/zhangchengc919/p/5384536.html
Copyright © 2011-2022 走看看