import numpy as np
import pandas as pd
df1=pd.DataFrame(np.ones((3,4))*0,columns=['a','b','c','d'])
df2=pd.DataFrame(np.ones((3,4))*1,columns=['a','b','c','d'])
df3=pd.DataFrame(np.ones((3,4))*2,columns=['a','b','c','d'])
a b c d
0 0.0 0.0 0.0 0.0
1 0.0 0.0 0.0 0.0
2 0.0 0.0 0.0 0.0
a b c d
0 1.0 1.0 1.0 1.0
1 1.0 1.0 1.0 1.0
2 1.0 1.0 1.0 1.0
a b c d
0 2.0 2.0 2.0 2.0
1 2.0 2.0 2.0 2.0
2 2.0 2.0 2.0 2.0
frame1 = pd.concat([df1,df2,df3],axis=0)#0为纵向，1为横向 一般合并都是选取1
print(frame1)
pd.concat([df1,df2],axis=1) #进行纵向合并
| a | b | c | d | a | b | c | d |
|---|
| 0 |
0.0 |
0.0 |
0.0 |
0.0 |
1.0 |
1.0 |
1.0 |
1.0 |
|---|
| 1 |
0.0 |
0.0 |
0.0 |
0.0 |
1.0 |
1.0 |
1.0 |
1.0 |
|---|
| 2 |
0.0 |
0.0 |
0.0 |
0.0 |
1.0 |
1.0 |
1.0 |
1.0 |
|---|
res=pd.concat([df1,df2,df3],axis=0)#0为纵向，1为横向
print(res)
a b c d
0 0.0 0.0 0.0 0.0
1 0.0 0.0 0.0 0.0
2 0.0 0.0 0.0 0.0
0 1.0 1.0 1.0 1.0
1 1.0 1.0 1.0 1.0
2 1.0 1.0 1.0 1.0
0 2.0 2.0 2.0 2.0
1 2.0 2.0 2.0 2.0
2 2.0 2.0 2.0 2.0
但是上面的结果有索引重复，去除索引重复可以采用ignore_index属性
res=pd.concat([df1,df2,df3],axis=0,ignore_index=True)#0为纵向，1为横向
print(res)
a b c d
0 0.0 0.0 0.0 0.0
1 0.0 0.0 0.0 0.0
2 0.0 0.0 0.0 0.0
3 1.0 1.0 1.0 1.0
4 1.0 1.0 1.0 1.0
5 1.0 1.0 1.0 1.0
6 2.0 2.0 2.0 2.0
7 2.0 2.0 2.0 2.0
8 2.0 2.0 2.0 2.0