1.创建一个员工表
字段 属性
id 整形(int)
name 字符串(varchar)(长度为20)
gender 字符串(长度为2)
birthday 日期型(date)
email 字符串(长度为10)
remark 字符串(长度为50)
CREATE TABLE workers( sid INT, sname VARCHAR(20), gender VARCHAR(2), birthday DATE, email VARCHAR(10), remark VARCHAR(50) );
2.修改表练习
2.1 在员工表基础上增加age列
2.2 修改email列长度为50
2.3 删除remark列
2.4 列名name修改为username
ALTER TABLE workers ADD COLUMN age INT; ALTER TABLE workers MODIFY COLUMN email VARCHAR(50); ALTER TABLE workers DROP COLUMN remark; ALTER TABLE workers CHANGE COLUMN sname username VARCHAR(20);
3 在员工表上练习数据的增删改操作
/*查看员工表格的所有数据*/ SELECT * FROM workers; /*查看员工表格的sid,username,age数据*/ SELECT sid,username,age FROM workers; /*查看员工表格的username,age数据*/ SELECT username,age FROM workers; /* 将以下数据填入表格*/ INSERT INTO workers VALUES(1,'张三丰','男','1367-10-21','12321222@qq.com',102); INSERT INTO workers VALUES(2,'达摩','男','1227-4-15','1121213242@126.com',54); INSERT INTO workers VALUES(3,'梅超风','女','1547-6-1','232442@163.com',44); INSERT INTO workers VALUES(4,'三体星人','未知','3012-8-15','12345678@fly.com',2000); INSERT INTO workers VALUES(5,'超级赛亚人','男','1985-2-3','whosyourdaday@sina.com',25); /*将sid为4的那一行的username改为“弗利萨”*/ UPDATE workers SET username = '弗利萨' WHERE sid = 4; /*删除age为2000的那一行*/ DELETE FROM workers WHERE age = 2000; /*将sid为4的那一行的age设为250*/ UPDATE workers SET age = 250 WHERE sid =4; /*将sid为5的那一行的username改为“孙悟空”,年龄改为26*/ UPDATE workers SET username = '孙悟空',age = '26' WHERE sid = 5;