Uva

A common typing error is to place the
hands on the keyboard one row to the
right of the correct position. So ‘Q’ is
typed as ‘W’ and ‘J’ is typed as ‘K’ and
so on. You are to decode a message typed in this manner.
Input
Input consists of several lines of text. Each line may contain digits, spaces, upper case letters (except
Q, A, Z), or punctuation shown above [except back-quote (‘)]. Keys labelled with words [Tab, BackSp,
Control, etc.] are not represented in the input.
Output
You are to replace each letter or punction symbol by the one immediately to its left on the ‘QWERTY’
keyboard shown above. Spaces in the input should be echoed in the output.
Sample Input
O S, GOMR YPFSU/
Sample Output

I AM FINE TODAY.

如果用if语句或者switch语句，太麻烦，一个比较好的方法是使用常量数组

AC代码：

#include <stdio.h>

char s[] = "`1234567890-=QWERTYUIOP[]\ASDFGHJKL;'ZXCVBNM,./";

int main()
{
	int i, c;
	while ((c = getchar()) != EOF) {
		for (i = 1; s[i] && (s[i] != c); i++); // 找错位之后的字符在常量表中的位置
		if (s[i]) {
			putchar(s[i - 1]); // 如果找到，则输出它的前一个字符
		}
		else {
			putchar(c);
		}
	}

	return 0;
}