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  • sql中的CONCAT函数运用实例1

    1 第一个例子

    2 第二个例子 select a.*,b.name as repayment_type_value,c.name as status_value, d.product_name, CONCAT(a.duration ,(case a.duration_type when 1 then '天' when 2 then '周' when 3 then '月' when 4 then '年' end)) as jkqx from loan_borrow a , (select * from SYS_DICTIONARIES where P_BM = 'repayment_type') b, (select * from SYS_DICTIONARIES where P_BM = 'status_s') c, loan_product d where b.BIANMA = a.repayment_type and c.BIANMA = a.status and a.product_id=d.product_id and a.rate >= #{pd.lastStart} and a.rate <= #{pd.lastEnd} and a.repayment_type=#{pd.repayment_type} and a.status=#{pd.status} 查询结果

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  • 原文地址:https://www.cnblogs.com/zhaoblog/p/6780642.html
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