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  • 简单计算器的C实现-函数指针,main函数传参

    /*
    * 程序功能:简单计算器,实现加减乘除平方
    * 作者版本日期:2015.11.08 zhouhb OK
    * 源代码:李明 《新概念C语言培训》第33集 C语言Shell命令解释器的实现
    * 代码存储位置 :133 /home/zhouhb/test/calculator.c
    * 整体思路:函数指针,main函数传参
    */

    #include <stdio.h>
    #include<stdlib.h>
    #include<string.h>

    int m_debug = 0;
    int (*pf)(int ,int);
    char opchar_math;//打印运算符

    //函数和名字对应
    struct operation{
    char name[8];
    int (*pf)(int,int);
    char opchar;
    };

    int add(int a,int b)
    {
    return a+b;
    }
    int sub(int a,int b)
    {
    return a-b;
    }
    int mul(int a,int b)
    {
    return a*b;
    }
    int divi(int a,int b)//div是C的函数
    {
    if(b<=0)
    return 0;
    return a/b;
    }
    int power(int a,int b)
    {
    int i = 0,num = 1;
    for(i=0;i<b;i++)
    {
    num = num * a;
    }
    return num;
    }
    struct operation op[]={
    {"add",add,'+'},
    {"sub",sub,'-'},
    {"mul",mul,'*'},
    {"div",divi,'/'},
    {"pow",power,'^'}
    };

    int math(int argc,char *argv[])
    {
    int a=0,b=0,num=0;
    int result;

    a = atoi(argv[1]);
    b = atoi(argv[2]);
    result = pf(a,b);
    printf("%d %c %d = %d ",a,opchar_math,b,result);
    }

    //函数和函数指针对应
    int command_do(int argc,char* argv[])
    {
    #if 0
    if(strncmp(argv[0],"add",3)==0)
    pf = add;
    if(strncmp(argv[0],"sub",3)==0)
    pf = sub;
    if(strncmp(argv[0],"mul",3)==0)
    pf = mul;
    if(strncmp(argv[0],"divi",4)==0)
    pf = divi;
    if(strncmp(argv[0],"pow",3)==0)
    pf = power;
    #endif

    int i = 0;
    for(i = 0;i<sizeof(op)/sizeof(op[0]);i++)
    {
    if(strcmp(argv[0],op[i].name)==0)
    {
    pf = op[i].pf;
    opchar_math = op[i].opchar;
    break;
    }
    }
    math(argc,argv);
    }

    //模拟main对输入进行处理
    void shell_parse(char* buff)
    {
    int argc = 0;
    char *argv[8];
    int state = 0;
    int i = 0;

    while(*buff)
    {
    char c = *buff;
    if(c == ' '&&state == 0)//" add 100"开始有空格
    state = 0;
    else if(c != ' '&& state == 0)//"add 100"解析第一个
    {
    argv[argc++] = buff;
    state = 1;
    }
    else if(c == ' ' && state ==1)//"a dd 100"解析完add遇到空格
    {
    *buff = '';
    state = 0;
    }
    else if(c != ' '&&state == 1)//"add 100"解析add中d
    {
    state = 1;
    }
    buff++;
    if(*buff == ' ')//传入有回车
    *buff = ' ';
    }

    argv[argc] = NULL;//避免出现乱编
    if(m_debug==1)
    {
    printf("argc = %d ",argc);
    for(i=0;i<argc;i++)
    {
    printf("argv[%d]:%s ",i,argv[i]);
    }
    }

    command_do(argc,argv);
    }

    int main(int argc,char* argv[],char* env[])
    {
    int i=0;
    char buff[254];
    int num=0;

    if(argc >1 && strlen(argv[1])>1 && strncmp(argv[1],"-d",2)==0)
    m_debug = 1;

    printf("input name num1 num2 ");
    while(1)
    {
    printf("NCCL#");
    fgets(buff,254,stdin);//不用scanf,gets
    if(m_debug)
    printf("buff=%s ",buff);
    shell_parse(buff);
    }

    #if 0
    printf("argc = %d ",argc);
    for(i=0;i<argc;i++)
    {
    printf("argv[%d]:%s ",i,argv[i]);
    }
    for(i=0;i<=3;i++)
    printf("env[%d]:%s ",i,env[i]);
    #endif

    }

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  • 原文地址:https://www.cnblogs.com/zhouhbing/p/4947772.html
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