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  • A1064. Complete Binary Search Tree

    A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties:

    • The left subtree of a node contains only nodes with keys less than the node's key.
    • The right subtree of a node contains only nodes with keys greater than or equal to the node's key.
    • Both the left and right subtrees must also be binary search trees.

    A Complete Binary Tree (CBT) is a tree that is completely filled, with the possible exception of the bottom level, which is filled from left to right.

    Now given a sequence of distinct non-negative integer keys, a unique BST can be constructed if it is required that the tree must also be a CBT. You are supposed to output the level order traversal sequence of this BST.

    Input Specification:

    Each input file contains one test case. For each case, the first line contains a positive integer N (<=1000). Then N distinct non-negative integer keys are given in the next line. All the numbers in a line are separated by a space and are no greater than 2000.

    Output Specification:

    For each test case, print in one line the level order traversal sequence of the corresponding complete binary search tree. All the numbers in a line must be separated by a space, and there must be no extra space at the end of the line.

    Sample Input:

    10
    1 2 3 4 5 6 7 8 9 0
    

    Sample Output:

    6 3 8 1 5 7 9 0 2 4

     1 #include<cstdio>
     2 #include<iostream>
     3 #include<vector>
     4 #include<algorithm>
     5 using namespace std;
     6 int tree[10001], N, index = 0, num[10001];
     7 bool cmp(int a, int b){
     8     return a < b;
     9 }
    10 void inOrder(int root){
    11     if(root > N)
    12         return;
    13     inOrder(root * 2);
    14     tree[root] = num[index++];
    15     inOrder(root * 2 + 1);
    16 }
    17 int main(){
    18     scanf("%d", &N);
    19     for(int i = 0; i < N; i++)
    20         scanf("%d", &num[i]);
    21     sort(num, num + N, cmp);
    22     inOrder(1);
    23     for(int i = 1; i <= N; i++){
    24         if(i != N)
    25             printf("%d ", tree[i]);
    26         else printf("%d", tree[i]);
    27     }
    28     cin >> N;
    29     return 0;
    30 }
    View Code

    总结:

    1、题意:给出一组数字,要求将它们建立成一颗二叉搜索树。因为结果不唯一,所以加了限制条件:要求搜索树是一颗完全二叉树。

    2、二叉搜索树的中序序列是从小到大的有序数列,所以对初始序列排序后就能得到搜索树的中序序列

    3、完全二叉树的树形状在给出节点个数N之后就是已知的。所以相当于已经知道了答案所求树的形状,但仅仅是树的节点没有填入值罢了。由于搜索树的中序序列已知,只需要按照中序遍历完全二叉树,在遍历的过程中填入搜索树的中序序列值即可。

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  • 原文地址:https://www.cnblogs.com/zhuqiwei-blog/p/8542835.html
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