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  • 判断身份证号是否合法

    -- =============================================
    -- Description: <判断身份证号是否合法,返回结果对应如下:>
    -- -2:含有非法字符
    -- -1:位数不正确(不为15或18位)
    -- 0:位数正确,但证号不合法
    -- 1:位数正确,且证号合法
    -- =============================================
    create FUNCTION [dbo].[f_checksfzh]
    (
     @ID varchar(30)  --要校验的证号
    )
    RETURNS int
    AS
    BEGIN
        DECLARE @ID15 varchar(30),@S18 int,@check char,@result int 
     if len(@ID)<>18 and len(@ID)<>15
      set @result = -1 --位数不正确
     else if len(@ID)=15
      begin
       if ISNUMERIC(@ID)=1
       set @result = 1
       else
       set @result = -2 --含有非法字符
      end
     else --18位
     begin 
      if ISNUMERIC(left(@ID,17))<>1 or (upper(right(@ID,1))<>'X' and ISNUMERIC(right(@ID,1))<>1)
       set @result = -2 --含有非法字符
      else
      begin
       set @ID15 = left(@ID,6)+substring(@ID,9,len(@ID) -9 )
       SET @S18 = ( (SUBSTRING(@ID15,1,1)*7) + (SUBSTRING(@ID15,2,1)*9) + (SUBSTRING(@ID15,3,1)*10)   
          + (SUBSTRING(@ID15,4,1)*5) + (SUBSTRING(@ID15,5,1)*8) + (SUBSTRING(@ID15,6,1)*4) + (1*2) + (9*1)   
          + (SUBSTRING(@ID15,7,1)*6) + (SUBSTRING(@ID15,8,1)*3) + (SUBSTRING(@ID15,9,1)*7)   
          + (SUBSTRING(@ID15,10,1)*9)+ (SUBSTRING(@ID15,11,1)*10)+ (SUBSTRING(@ID15,12,1)*5)   
          + (SUBSTRING(@ID15,13,1)*8) +(SUBSTRING(@ID15,14,1)*4) + (SUBSTRING(@ID15,15,1)*2) ) % 11  
           
       if @S18 = 0 set @check='1' 
       if @S18 = 1 set @check='0' 
       if @S18 = 2 set @check='X' 
       if @S18 = 3 set @check='9' 
       if @S18 = 4 set @check='8' 
       if @S18 = 5 set @check='7' 
       if @S18 = 6 set @check='6' 
       if @S18 = 7 set @check='5' 
       if @S18 = 8 set @check='4' 
       if @S18 = 9 set @check='3' 
       if @S18 = 10 set @check='2' 
       if @check=right(upper(@ID),1) set @result=1
       else set @result=0
      END
     end
        RETURN @result  
    END

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  • 原文地址:https://www.cnblogs.com/zhycyq/p/2585739.html
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