zoukankan      html  css  js  c++  java
  • Java [Leetcode 125]Valid Palindrome

    题目描述:

    Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases.

    For example,
    "A man, a plan, a canal: Panama" is a palindrome.
    "race a car" is not a palindrome.

    Note:
    Have you consider that the string might be empty? This is a good question to ask during an interview.

    For the purpose of this problem, we define empty string as valid palindrome.

    解题思路:

    设置两个指针,一个在字符串头部,一个在字符串尾部,分别向中间移动,遇到非字母或数字则继续向中间移动,如两个都为字母或者数字,那么则比较两者是否相同。

    代码如下:

    public class Solution {
        public boolean isPalindrome(String s) {
        	int i = 0, j = s.length() - 1;
        	char head, tail;
        	if(j < 0)
        		return true;
        	while(i < j){
        		head = s.charAt(i);
        		tail = s.charAt(j);
        		if(!Character.isLetterOrDigit(head)){
        			i++;
        		} 
        		if(!Character.isLetterOrDigit(tail)){
        			j--;
        		}
        		if(Character.isLetterOrDigit(head) && Character.isLetterOrDigit(tail)){
        			if(Character.toLowerCase(head) != Character.toLowerCase(tail)){
        				return false;
        			}
        			i++;
        			j--;
        		}
        	}
        	return true;
        }
    }
    

      

  • 相关阅读:
    FTP文件传输应用分析
    A*寻路算法
    Asp.net页面事件引发后台程序处理原理
    开发人员的基本原则(转)
    定位new表达式
    常量对象的动态分配和释放
    PostThreadMessage使用
    最美丽的数学公式
    仿函数
    CF1598EStaircases【计数】
  • 原文地址:https://www.cnblogs.com/zihaowang/p/5199517.html
Copyright © 2011-2022 走看看