题目描述:
Given a linked list, determine if it has a cycle in it.
解题思路:
快的指针和慢的指针
代码如下:
# Definition for singly-linked list. # class ListNode(object): # def __init__(self, x): # self.val = x # self.next = None class Solution(object): def hasCycle(self, head): """ :type head: ListNode :rtype: bool """ slow = fast = head while slow and fast and fast.next: slow = slow.next fast = fast.next.next if slow == fast: return True return False