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  • *的组合

    class Solution {
    public:
        void dfs(string digits, int idx, map<char,string> hash, string path, vector<string>& res){
            if(idx==digits.size()){
                res.push_back(path);
                return;
            }

            for(char ch:hash[digits[idx]]){
                path+=ch;
                dfs(digits,idx+1,hash,path,res);
                path.pop_back();
            }
        }

        vector<string> letterCombinations(string digits) {
            if(digits.size()==0) return {};
            map<char,string> hash={{'2',"abc"},{'3',"def"},{'4',"ghi"},{'5',"jkl"},{'6',"mno"},{'7',"pqrs"},{'8',"tuv"},{'9',"wxyz"}};
            string path="";
            vector<string> res;

            dfs(digits,0, hash,path,res);

            return res;
        }
    };
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  • 原文地址:https://www.cnblogs.com/zijidan/p/12435396.html
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