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  • BZOJ 3697 采药人的路径

    点分。随便记录下这个点到上面有没有len=0的点,然后直接统计答案。

    1A了赞。

    #include<iostream>
    #include<cstdio>
    #include<cstring>
    #include<algorithm>
    #define maxv 100050
    #define maxe 200050
    #define inf 1000000007
    using namespace std;
    int n,x,y,z,g[maxv],nume=1,add,cnt1[maxv*30],cnt2[maxv*30],cnts[maxv*30],sum,root;
    int size[maxv],mx[maxv],dis[maxv];
    long long ans=0;
    struct edge
    {
        int v,w,nxt;
    }e[maxe];
    bool vis[maxv];
    void addedge(int u,int v,int w)
    {
        e[++nume].v=v;e[nume].w=(w==1)?1:-1;
        e[nume].nxt=g[u];g[u]=nume;
    }
    void get_root(int x,int fath)
    {
        size[x]=1;mx[x]=0;
        for (int i=g[x];i;i=e[i].nxt)
        {
            int v=e[i].v;
            if (v==fath || vis[v]) continue;
            get_root(v,x);
            size[x]+=size[v];mx[x]=max(mx[x],size[v]);
        }
        mx[x]=max(mx[x],sum-size[x]);
        if (mx[x]<mx[root]) root=x;
    }
    void dfs1(int x,int fath,int type)
    {
        cnts[dis[x]+add]++;
        if (type>0)
        {
            if (dis[x]==0) ans+=(long long)cnt1[add]+(cnts[add]>=2);
            else
            {
                if (cnts[dis[x]+add]>=2) ans+=(long long)cnt1[-dis[x]+add];
                else ans+=(long long)cnt2[-dis[x]+add];
            }
        }
        else
        {
            cnt1[dis[x]+add]++;
            if (cnts[dis[x]+add]>=2) cnt2[dis[x]+add]++;
        }
        for (int i=g[x];i;i=e[i].nxt)
        {
            int v=e[i].v;
            if (vis[v] || v==fath) continue;
            dis[v]=dis[x]+e[i].w;dfs1(v,x,type);
        }
        cnts[dis[x]+add]--;
    }
    void dfs2(int x,int fath)
    {
        size[x]=1;cnt1[dis[x]+add]=cnt2[dis[x]+add]=0;
        for (int i=g[x];i;i=e[i].nxt)
        {
            int v=e[i].v;
            if (vis[v] || v==fath) continue;
            dfs2(v,x);
            size[x]+=size[v];
        }
    }
    void solve(int x)
    {
        vis[x]=1;
        for (int i=g[x];i;i=e[i].nxt)
        {
            int v=e[i].v;
            if (vis[v]) continue;
            dis[v]=e[i].w;dfs1(v,0,1);
            dis[v]=e[i].w;dfs1(v,0,-1);
        }
        for (int i=g[x];i;i=e[i].nxt)
        {
            int v=e[i].v;
            if (vis[v]) continue;
            dis[v]=e[i].w;dfs2(v,0);
        }
        for (int i=g[x];i;i=e[i].nxt)
        {
            int v=e[i].v;
            if (vis[v]) continue;
            sum=size[v];root=0;get_root(v,0);
            solve(root);
        }
    }
    int main()
    {
        scanf("%d",&n);add=n+1;mx[0]=inf;
        for (int i=1;i<=n-1;i++)
        {
            scanf("%d%d%d",&x,&y,&z);
            addedge(x,y,z);addedge(y,x,z);
        }
        sum=n;root=0;get_root(1,0);
        solve(root);
        printf("%lld
    ",ans);
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/ziliuziliu/p/6535779.html
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