CodeForces Round #521 (Div.3) B. Disturbed People

http://codeforces.com/contest/1077/problem/B

There is a house with nn flats situated on the main street of Berlatov. Vova is watching this house every night. The house can be represented as an array of nn integer numbers a1,a2,…,ana1,a2,…,an, where ai=1ai=1 if in the ii-th flat the light is on and ai=0ai=0 otherwise.

Vova thinks that people in the ii-th flats are disturbed and cannot sleep if and only if 1<i<n1<i<n and ai−1=ai+1=1ai−1=ai+1=1 and ai=0ai=0.

Vova is concerned by the following question: what is the minimum number kk such that if people from exactly kk pairwise distinct flats will turn off the lights then nobody will be disturbed? Your task is to find this number kk.

Input

The first line of the input contains one integer nn (3≤n≤1003≤n≤100) — the number of flats in the house.

The second line of the input contains nn integers a1,a2,…,ana1,a2,…,an (ai∈{0,1}ai∈{0,1}), where aiai is the state of light in the ii-th flat.

Output

Print only one integer — the minimum number kk such that if people from exactly kk pairwise distinct flats will turn off the light then nobody will be disturbed.

Examples

input

Copy

10
1 1 0 1 1 0 1 0 1 0

output

Copy

2

input

Copy

5
1 1 0 0 0

output

Copy

0

input

Copy

4
1 1 1 1

output

Copy

0

题解：刚开始没看懂题意后来找了翻译 炒鸡简单 如果 a[i] = 0 && a[i - 1] = 1 && a[i + 1] = 1 那么 i 会被影响 应该关掉 a[i + 1] 的灯，即变成 $0$

代码：

#include <bits/stdc++.h>
using namespace std;

const int maxn = 1e5 + 10;
int n;
int a[maxn];

int main() {
    scanf("%d", &n);
    for(int i = 1; i <= n; i ++)
        scanf("%d", &a[i]);

    int ans = 0;
    for(int i = 2; i < n; i ++) {
        if(a[i] == 0 && a[i - 1] == 1 && a[i + 1] == 1) {
            ans ++;
            a[i + 1] = 0;
        }
    }
    printf("%d
", ans);
    return 0;
}

　　

让人捉鸡的英语理解能力。。。难受