zoukankan      html  css  js  c++  java
  • hdu 3791 二叉搜索树

    简单的二叉搜索树建树过程

    #include<stdio.h>
    #include<string.h>
    int tree1[1500], tree2[1500];
    char s[1000], k[1000];
    void build1()
    {
        int i;
        tree1[1] = s[0] - '0';
        int y = strlen(s);
        for (i = 1; i < y; i++)
        {
            int now = 1;
            while (1)
            {
                if (tree1[now] == -1) break;
                else
                {
                    if (tree1[now] < s[i] - '0')now = now * 2 + 1;
                    else now = now * 2;
                }
            }
            tree1[now] = s[i] - '0';
        }
    }
    void build2()
    {
        int i;
        tree2[1] = k[0] - '0';
        int y = strlen(k);
        for (i = 1; i < y; i++)
        {
            int now = 1;
            while (1)
            {
                if (tree2[now] == -1) break;
                else
                {
                    if (tree2[now] < k[i] - '0') now = now * 2 + 1;
                    else now = now * 2;
                }
            }
            tree2[now] = k[i] - '0';
        }
    }
    int main()
    {
        int n, i, j, g;
        while (~scanf("%d", &n))
        {
            if (n == 0) break;
            scanf("%s", s);
    
            for (i = 0; i < 1350; i++) tree1[i] = -1;
            build1();
            for (i = 0; i < n; i++)
            {
                for (g = 0; g < 1350; g++) tree2[g] = -1;
                scanf("%s", k);
                build2();
                for (j = 1; j < 1400; j++)
                {
                    if (tree1[j] != tree2[j]) break;
                }
                if (j == 1400) puts("YES");
                else puts("NO");
            }
        }
        return 0;
    }
  • 相关阅读:
    hdu 1195 Open the Lock
    hdu 1180 诡异的楼梯
    hdu 1175 连连看
    背包(采药)
    LCS模板,求长度,并记录子串
    hdu 1159 Common Subsequence
    hdu 1231 最大连续子序列
    DP的简单应用
    hdu 1728 逃离迷宫
    点击页面其他地方,关闭弹框
  • 原文地址:https://www.cnblogs.com/zufezzt/p/4438626.html
Copyright © 2011-2022 走看看