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  • SQL练习

    --18.
    create table grade(low number(3),upp number (3),rank char(1));
    insert into gGrade values(90,100,'A');
    insert into grade values(80,89,'B');
    insert into grade values(70,79,'C');
    insert into grade values(60,69,'D');
    insert into grade values(0,59,'E');

    grade表:

    select SNO,CNO,rank from t_hq_score,grade where DEGREE between low and upp;

    --19.
    select * from t_hq_score where CNO='3-105'and degree >all(select degree from t_hq_score where SNO='109');

    --21.
    select * from t_hq_score where DEGREE >(select degree from t_hq_score where cno='3-105'and sno='109');

    --22.
    --最初
    select sno,sname,sbirthday from t_hq_student where sbirthday in (select sbirthday from t_hq_student where sno='108');
    --改过后
    select sno,sname,sbirthday from t_hq_student where to_char( sbirthday,'yyyy' ) = to_char( (select sbirthday from t_hq_student where sno='108'),'yyyy');

    --23.
    select * from t_hq_score where cno in(select cno from t_hq_course where tno in(select tno from t_hq_teacher where tname='张旭'));

    --24.
    select tname from t_hq_teacher where tno in(select tno from t_hq_course where cno in (select cno from t_hq_score group by cno having count(*)>5));

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  • 原文地址:https://www.cnblogs.com/zxw0004/p/4936524.html
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