需求:给定任意一个月,如何按照中国周的习惯,把一个月分成四个时间段
(1)以自然周为划分依据
(2)不能跨月
(3)把首尾自然周,天数较少的合并到其最近的自然周里面
(4)最后结果应该是吧一个月分成四个时间段,并给出每段的起止日期
大概需求就如上所述,不废话,上代码:(以封装好在main()函数里,直接copy即可,记得导相应的包和新建实体类)
public class one_month_four_week { public static void main(String[] args) { int year = 2017; int month = 10;//改成你要的年月,运行即可查看结果 Calendar cal = Calendar.getInstance(); cal.set(Calendar.YEAR, year); cal.set(Calendar.MONTH, month - 1);// -1才正确 int days = cal.getActualMaximum(Calendar.DATE);// Calendar.DAY_OF_MONTH也对 System.out.println("首先,计算这个月有" + days + "天"); String[] weekDays = { "星期日", "星期一", "星期二", "星期三", "星期四", "星期五", "星期六" };// 国外一周起始 int[] chinaWeek = { 7, 1, 2, 3, 4, 5, 6 };// 对应成中国一周的第几天 SimpleDateFormat str_date_format = new SimpleDateFormat("yyyy-MM-dd"); List<EachDayAttr> monthDay = new ArrayList<>(); int week_of_month = 1; for (int i = 1; i <= days; i++) { EachDayAttr oneDay = new EachDayAttr(); oneDay.setWhich(i); // 计算这个月的每一天,对应星期几 String dayStr = year + "-" + month + "-" + i; Date daysDate = null; try { daysDate = str_date_format.parse(dayStr); } catch (ParseException e) { e.printStackTrace(); } cal.setTime(daysDate); int w1 = cal.get(Calendar.DAY_OF_WEEK) - 1; // 指示一个星期中的第几天 int which_day_chinaWeek = chinaWeek[w1]; System.out.println("该月的第"+ i +"天,该星期(外国习惯)的第"+ w1 +"天:"+ weekDays[w1] +">>对应中国周的第"+ which_day_chinaWeek +"天!"); //关键:该月每一天对应,中国周里面的第几周 if (which_day_chinaWeek == 1 && monthDay.size() > 0) {// 星期一,中国习惯里新的一周的开始 week_of_month++; oneDay.setWeek(week_of_month); } else { oneDay.setWeek(week_of_month); } monthDay.add(oneDay); } // 分组:按中国习惯分组 Map<Integer, List<EachDayAttr>> weekGroup = new TreeMap<>(); for (EachDayAttr oneDay : monthDay) { if (weekGroup.containsKey(oneDay.getWeek())) { weekGroup.get(oneDay.getWeek()).add(oneDay); } else { List<EachDayAttr> addGroup = new ArrayList<>(); addGroup.add(oneDay); weekGroup.put(oneDay.getWeek(), addGroup); } } // 再分组:合并成四周 if (weekGroup.size() == 4) { // weekGroup不做处理 } else if (weekGroup.size() == 5) { if (weekGroup.get(1).size() < weekGroup.get(5).size()) { weekGroup.get(2).addAll(weekGroup.get(1)); weekGroup.remove(1); } else { weekGroup.get(4).addAll(weekGroup.get(5)); weekGroup.remove(5); } } else if (weekGroup.size() == 6) { weekGroup.get(2).addAll(weekGroup.get(1)); weekGroup.get(5).addAll(weekGroup.get(6)); weekGroup.remove(1); weekGroup.remove(6); } // 吧weekGroup按天数排序,取最小为开始日期,最大为结束日期即可 for (Entry<Integer, List<EachDayAttr>> entry : weekGroup.entrySet()) { Collections.sort(entry.getValue(), new Comparator<EachDayAttr>() { public int compare(EachDayAttr day1, EachDayAttr day2) { return day1.getWhich() - day2.getWhich(); } }); } // 最后从分好组、排好序的weekGroup中取值封装 // weekGroup-->entry中健为整数,而值为list<?>集合 Map<Integer, String[]> rtResult = new HashMap<>(); int signWeek = 1; for (Entry<Integer, List<EachDayAttr>> entry : weekGroup.entrySet()) { String[] addResult = new String[2]; int firstDay = entry.getValue().get(0).getWhich(); int lastDay = entry.getValue().get(entry.getValue().size() - 1).getWhich(); addResult[0] = year + "-" + month + "-" + firstDay; addResult[1] = year + "-" + month + "-" + lastDay; rtResult.put(signWeek, addResult); signWeek++; } // 至此,输出看下结果 for (Entry<Integer, String[]> entry : rtResult.entrySet()) { System.out.println("----该月第"+ entry.getKey() +"周-----"); System.out.println("开始日期:" + entry.getValue()[0]); System.out.println("结束日期:" + entry.getValue()[1]); } } }
总结:上面方法。涉及知识点其实挺多,也是日常项目中遇到的比较多的,比如Calendar这个出来日期的类,还有分组排序、map的遍历等;
加上自定义的实体类,强迫症的小伙伴可以看下:
public class EachDayAttr { private int which; private int week; private int flag;
//get和set方法省略 }
最后。附上SQL大神直接用sql是怎么把一个月按中国周分的(这里一个月最多会有六周,为了更清楚,笔者有改动,但该sql精华不变)
select min(dt) 一周开始, max(dt) 一周结束, count(flag) 该周天数, ROW_NUMBER() over(order by 1) as 周数 from ( select level rn, trunc(to_date(201707,'yyyymm'), 'mm') + level - 1 dt, max(decode (to_char(trunc(to_date(201707,'yyyymm'), 'mm') + level - 1, 'd'), 2, level, 0)) over(order by level) flag from dual connect by level <= last_day(trunc(to_date(201707,'yyyymm'))) - trunc(to_date(201707,'yyyymm'), 'mm') + 1 ) group by flag order by min(rn)
这是在mybatis里面实现的,传入的参数是整形的年月,比如int yyyymm = 201707;