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  • 查缺补漏,对知识点和练习题进行归纳总结

    朱忠原

    1. 让用户输入金额
    2. 选择要购买的商品加入购物车
    3. 当商品的总价超过了你的金额提示余额不足
    4. 让用户输入N结算,输入Q退出
    5. 用户退出后提示消费了多少,还剩多少
    '''

    # dic1 = {'火女':'安妮','火男':'布兰德','维恩':'暗影猎手','剑豪':'哈莎阁'}
    # print(dic1.items())
    goods = [
    {'name':'电脑','price':1999},
    {'name':'鼠标','price':10},
    {'name':'美女','price':50},
    {'name':'游艇','price':20},
    {'name':'火箭','price':250},
    ]

    fei_yong = 0
    shop_car = {}
    money = input("请输入你的金额")
    if money.isdigit():
    #这是真钱
    while 1:
    for i in range(len(goods)):
    print(i+1,goods[i]["name"],goods[i]["price"])

    choose = input("请输入你选择的商品序号:(N. 结算,Q. 退出)")
    if choose.isdigit() and 0 < int(choose) < len(goods):
    int_index = int(choose)-1
    if shop_car.get(int_index) == None:
    shop_car[int_index] =1
    else:
    shop_car[int_index] = shop_car[int_index]
    print(shop_car)
    elif choose.upper() == 'N':
    # 结算
    # ... == pass
    # 1.2 - 1.0 == 0.2 获取到是False 一个数学算法(牛顿偏离法)导致的

    for f in shop_car:
    fei_yong = fei_yong + shop_car[f] * goods[f]['price']

    if int(money) - fei_yong >= 0:
    for k in shop_car:
    print(f'您购买的商品是{goods[k]["name"]},单价{goods[k]["price"]},数量{shop_car[k]}')
    else:
    print('余额不足')
    elif choose.upper() == "Q":
    print(f'您本次消费{fei_yong},剩余金额{int(money)-fei_yong}')
    break

    else:
    print("你输入有误,请重新输入:")
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  • 原文地址:https://www.cnblogs.com/zzy7372/p/9463132.html
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