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  • 85. 最大矩形

    给定一个仅包含 0 和 1 的二维二进制矩阵,找出只包含 1 的最大矩形,并返回其面积。

    示例:

    输入:
    [
      ["1","0","1","0","0"],
      ["1","0","1","1","1"],
      ["1","1","1","1","1"],
      ["1","0","0","1","0"]
    ]
    输出: 6

    class Solution {
        public int maximalRectangle(char[][] matrix) {
            if(matrix == null || matrix.length == 0 || matrix[0].length == 0) return 0;
            int m = matrix.length;
            int n = matrix[0].length;
            int res = 0;
            int[] dp = new int[matrix[0].length];
            for(int i = 0;i < m;i++){
                for(int j = 0;j < n;j++){
                    dp[j] = matrix[i][j] == '1' ? dp[j] + 1 : 0;
                }
                res = Math.max(res,getL(dp));
            }
            return res;
        }
        private int getL(int[] nums){
            //单调增栈
            Stack<Integer> stack = new Stack<>();
            stack.push(-1);
            int res = 0;
            for(int i = 0;i < nums.length;i++){
                while(stack.peek() != -1 && nums[stack.peek()] >= nums[i]){
                    res = Math.max(res,nums[stack.pop()] * (i - stack.peek() - 1));
                }
                stack.push(i);
            }
            while(stack.peek() != -1){
                res = Math.max(res, nums[stack.pop()] * (nums.length - stack.peek() - 1));
            }
            return res;
        }
    }
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  • 原文地址:https://www.cnblogs.com/zzytxl/p/12681856.html
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