JAVA——A+B
——————我的第一道JAVA
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 241566 Accepted Submission(s):
46567
Problem Description
I have a very simple problem for you. Given two
integers A and B, your job is to calculate the Sum of A + B.
Input
The first line of the input contains an integer
T(1<=T<=20) which means the number of test cases. Then T lines follow,
each line consists of two positive integers, A and B. Notice that the integers
are very large, that means you should not process them by using 32-bit integer.
You may assume the length of each integer will not exceed 1000.
Output
For each test case, you should output two lines. The
first line is "Case #:", # means the number of the test case. The second line is
the an equation "A + B = Sum", Sum means the result of A + B. Note there are
some spaces int the equation. Output a blank line between two test
cases.
Sample Input
2
1 2
112233445566778899 998877665544332211
Sample Output
Case 1:
1 + 2 = 3
Case 2:
112233445566778899 + 998877665544332211 = 1111111111111111110
大数题,我的第一道JAVA
![](https://images.cnblogs.com/OutliningIndicators/ContractedBlock.gif)
import java.util.Scanner; import java.math.BigInteger; public class Main { final int maxn=1000100; public static void main(String[] args){ Scanner in=new Scanner(System.in); int T; T=in.nextInt(); for(int i=1;i<=T;i++){ BigInteger a,b,c; a=in.nextBigInteger(); b=in.nextBigInteger(); c=a.add(b); System.out.println("Case "+i+":"); System.out.println(a.toString()+" + "+b.toString()+" = "+c.toString()); if(i<T) System.out.println(); } } }