zoukankan      html  css  js  c++  java
  • codeforces #317 div2 A. Arrays (水)

    A. Arrays
    time limit per test
    2 seconds
    memory limit per test
    256 megabytes
    input
    standard input
    output
    standard output

    You are given two arrays A and B consisting of integers, sorted in non-decreasing order. Check whether it is possible to choose knumbers in array A and choose m numbers in array B so that any number chosen in the first array is strictly less than any number chosen in the second array.

    Input

    The first line contains two integers nA, nB (1 ≤ nA, nB ≤ 105), separated by a space — the sizes of arrays A and B, correspondingly.

    The second line contains two integers k and m (1 ≤ k ≤ nA, 1 ≤ m ≤ nB), separated by a space.

    The third line contains nA numbers a1, a2, ... anA ( - 109 ≤ a1 ≤ a2 ≤ ... ≤ anA ≤ 109), separated by spaces — elements of array A.

    The fourth line contains nB integers b1, b2, ... bnB ( - 109 ≤ b1 ≤ b2 ≤ ... ≤ bnB ≤ 109), separated by spaces — elements of array B.

    Output

    Print "YES" (without the quotes), if you can choose k numbers in array A and m numbers in array B so that any number chosen in array Awas strictly less than any number chosen in array B. Otherwise, print "NO" (without the quotes).

    Sample test(s)
    input
    3 3
    2 1
    1 2 3
    3 4 5
    output
    YES
    input
    3 3
    3 3
    1 2 3
    3 4 5
    output
    NO
    input
    5 2
    3 1
    1 1 1 1 1
    2 2
    output
    YES
    Note

    In the first sample test you can, for example, choose numbers 1 and 2 from array A and number 3 from array B (1 < 3 and 2 < 3).

    In the second sample test the only way to choose k elements in the first array and m elements in the second one is to choose all numbers in both arrays, but then not all the numbers chosen in A will be less than all the numbers chosen in B.

     应该3分钟过的题。。。

    结果花了8分钟。。。ssssad

     1 /*************************************************************************
     2     > File Name: code/cf/#317/A.cpp
     3     > Author: 111qqz
     4     > Email: rkz2013@126.com 
     5     > Created Time: 2015年08月23日 星期日 00时29分47秒
     6  ************************************************************************/
     7 
     8 #include<iostream>
     9 #include<iomanip>
    10 #include<cstdio>
    11 #include<algorithm>
    12 #include<cmath>
    13 #include<cstring>
    14 #include<string>
    15 #include<map>
    16 #include<set>
    17 #include<queue>
    18 #include<vector>
    19 #include<stack>
    20 #include<cctype>
    21 #define y1 hust111qqz
    22 #define yn hez111qqz
    23 #define j1 cute111qqz
    24 #define ms(a,x) memset(a,x,sizeof(a))
    25 #define lr dying111qqz
    26 using namespace std;
    27 #define For(i, n) for (int i=0;i<int(n);++i)  
    28 typedef long long LL;
    29 typedef double DB;
    30 const int inf = 0x3f3f3f3f;
    31 const int N=1E5+7;
    32 int na,nb,k,m;
    33 int a[N],b[N];
    34 int main()
    35 {
    36   #ifndef  ONLINE_JUDGE 
    37     freopen("in.txt","r",stdin); 
    38   #endif
    39     cin>>na>>nb;
    40     cin>>k>>m;
    41     for ( int i = 1 ; i <= na ; i++){
    42     scanf("%d",&a[i]);
    43     }
    44     for ( int i  = 1 ; i<= nb ; i++){
    45     scanf("%d",&b[i]);
    46     }
    47     if (a[k]<b[nb-m+1]){
    48     puts("YES");
    49     }
    50     else
    51     {
    52     puts("NO");
    53     }
    54   
    55   
    56  #ifndef ONLINE_JUDGE  
    57   fclose(stdin);
    58   #endif
    59     return 0;
    60 }
    View Code
  • 相关阅读:
    python hashlib模块
    OS模块-提供对操作系统进行调用的接口
    For循环
    python --time()函数
    使用docker部署prometheus和grafana 并监控mysql 配置告警
    记换换回收一个js逆向分析
    mitmproxy 在windows上的使用
    elasticsearch_dsl 的nested
    利用谷歌插件破解今日头条的新闻ajax参数加密,新手都能懂
    aiohttp爬虫的模板,类的形式
  • 原文地址:https://www.cnblogs.com/111qqz/p/4752657.html
Copyright © 2011-2022 走看看