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  • 靶形数独

    搜索,据说反着输入有奇效,要用位运算,然后剪不剪枝无所谓,没提速。

    #include<iostream>
    #include<cstdio>
    using namespace std;
    int ans,tot,sum,sum1;
    bool flag;
    int board[10][10],val[10][10],squre[6][6];
    int row[10],col[10];
    inline int Max(int x,int y)
    {
        return x>y?x:y;
    }
    inline int calc()
    {
        int ret=0;
        for(int i=0;i<9;i++)
        {
            for(int j=0;j<9;j++) ret+=val[i][j]*board[i][j];
        }
        return ret;
    }
    
    void dfs(int x,int y)
    {    
        if(tot+sum*9*9+sum1<ans) return;
    //    cout<<x<<" "<<y<<endl;
        if(x==8&&y==9)
        {
            flag=true;
            ans=Max(ans,tot+sum1);
    //        cout<<"a"<<endl;
            return;
        }
        if(y==9)
        {
            dfs(x+1,0);
            return;
        }    
        
        if(board[x][y])
        {
            dfs(x,y+1);
            return;
        }
    
        for(int i=1;i<=9;i++)
        {
            if(!(row[x]&(1<<i))&&!(col[y]&(1<<i))&&!(squre[x/3][y/3]&(1<<i))) 
            {
                board[x][y]=i;
                sum--;
                squre[x/3][y/3]^=(1<<i);
                row[x]^=(1<<i);
                col[y]^=(1<<i);
                tot+=val[x][y]*i;
                dfs(x,y+1);
                sum++;
                squre[x/3][y/3]^=(1<<i);
                row[x]^=(1<<i);
                col[y]^=(1<<i);
                tot-=val[x][y]*i;
                board[x][y]=0;
            }
        }
    }
    int main()
    {
        for(int i=0;i<9;i++)
        {
            val[0][i]=val[i][0]=val[8][i]=val[i][8]=6;
        }
        for(int i=1;i<8;i++)
        {
            val[1][i]=val[i][1]=val[7][i]=val[i][7]=7;
        }
        for(int i=2;i<7;i++)
        {
            val[2][i]=val[i][2]=val[6][i]=val[i][6]=8;
        }
        for(int i=3;i<6;i++)
        {
            val[3][i]=val[i][3]=val[5][i]=val[i][5]=9;
        } 
        val[4][4]=10;
        for(int i=0;i<9;i++)
        {
            for(int j=0;j<9;j++)
            {
                scanf("%d",&board[i][j]); 
                sum+=board[i][j]==0;
                sum1+=board[i][j]*val[i][j];
                row[i]^=(1<<board[i][j]);
                col[j]^=(1<<board[i][j]);
                squre[i/3][j/3]^=(1<<board[i][j]);
            }
        } 
        ans=sum1;
        dfs(0,0);
        if(!flag) cout<<-1<<endl; else
        cout<<ans<<endl;
        return 0;
    } 
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  • 原文地址:https://www.cnblogs.com/19992147orz/p/6081327.html
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