傻逼题;
获取n/k;
对n/k的奇偶性讨论一下就好
0
#include <bits/stdc++.h>
#define LL long long
using namespace std;
LL n,k;
int main(){
//freopen("F:\rush.txt","r",stdin);
scanf("%lld%lld",&n,&k);
LL temp = n/k;
if (temp%2==1){
puts("YES");
}else{
puts("NO");
}
return 0;
}