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  • 【codeforces 810B】Summer sell-off

    【题目链接】:http://codeforces.com/contest/810/problem/B

    【题意】

    每天有ki件物品,你知道每天能卖掉li件;
    然后让你选f天;
    这f天,可以将ki乘上2;
    每天结束之后物品清空;
    问你最多能卖多少件物品;

    【题解】

    先算出来不用f天的乘2效果;
    卖出的物品数目;
    然后考虑;
    乘2之后,能够多卖的物品数量;
    排个序,逆序排,然后取前f个就好;
    累加答案;

    【Number Of WA

    0

    【完整代码】

    #include <bits/stdc++.h>
    using namespace std;
    #define lson l,m,rt<<1
    #define rson m+1,r,rt<<1|1
    #define LL long long
    #define rep1(i,a,b) for (int i = a;i <= b;i++)
    #define rep2(i,a,b) for (int i = a;i >= b;i--)
    #define mp make_pair
    #define pb push_back
    #define fi first
    #define se second
    #define ms(x,y) memset(x,y,sizeof x)
    #define Open() freopen("F:\rush.txt","r",stdin)
    #define Close() ios::sync_with_stdio(0),cin.tie(0)
    
    typedef pair<int,int> pii;
    typedef pair<LL,LL> pll;
    
    const int dx[9] = {0,1,-1,0,0,-1,-1,1,1};
    const int dy[9] = {0,0,0,-1,1,-1,1,-1,1};
    const double pi = acos(-1.0);
    const int N = 1e5+100;
    
    int n,f;
    LL k[N],l[N];
    LL b[N];
    LL ans = 0;
    
    int main()
    {
        //Open();
        Close();//scanf,puts,printf not use
        //init??????
        cin >> n >> f;
        rep1(i,1,n)
            cin >> k[i] >> l[i];
        rep1(i,1,n)
            ans+=min(k[i],l[i]);
        rep1(i,1,n)
        {
            if (k[i]<l[i])
            {
                l[i]-=k[i];
                b[i] = min(k[i],l[i]);
            }
            else
            {//k[i]>=l[i];
                b[i] = 0;
            }
        }
        sort(b+1,b+1+n);
        reverse(b+1,b+1+n);
        rep1(i,1,f)
            ans+=b[i];
        cout << ans << endl;
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/AWCXV/p/7626307.html
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