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  • bzoj2243 树刨+线段树区间合并

    题意:区间修改树上两点间的颜色种类,区间查询树上两点间的线段数。
    思路:树刨+线段树,区间合并是第一次写。思路为线段树维护左端点和右端点的颜色,合并时相同就–。具体实现不太好写。
    代码:

    #include <bits/stdc++.h>
    using namespace std;
    #define ll long long
    #define forn(i,n) for(int i=0;i<n;i++)
    #define for1(i,n) for(int i=1;i<=n;i++)
    #define IO ios::sync_with_stdio(false);cin.tie(0)
    const int maxn = 1e5+5;
    
    int a[maxn],top[maxn],sz[maxn],son[maxn],deep[maxn],p[maxn],par[maxn],fp[maxn],id,now;
    vector<int>e[maxn];
    class segment_tree{
        public:
        #define nd node[now]
        #define ndl node[now<<1]
        #define ndr node[now<<1|1]
        struct segment_node{
            int l,r,v,flag,cl,cr;
            void update(int x){
                flag = cl = cr = x,v = 1;
            }
        }node[maxn<<2];
        void pushup(int now){
    		nd.cl = ndl.cl,nd.cr = ndr.cr; 
            nd.v = ndl.v+ndr.v;
            if(ndl.cr==ndr.cl) nd.v--;
        }
        void pushdown(int now){
            if(nd.flag!=-1){
                ndl.update(nd.flag);
                ndr.update(nd.flag);
                nd.flag = -1;
            }
        }
        void maketree(int l,int r,int now = 1){
            nd = {l,r,-1,-1,-1,-1};
            if(l==r){
                nd.v = 1,nd.cl = nd.cr = a[fp[l]];
                return;
            }
            maketree(l,l+r>>1,now<<1);
            maketree((l+r>>1)+1,r,now<<1|1);
            pushup(now);
        }
        void update(int l,int r,int v,int now = 1){
            if(l<=nd.l&&r>=nd.r){
                nd.update(v);
                return;
            }
            pushdown(now);
            if(l<=ndl.r) update(l,r,v,now<<1);
            if(r>=ndr.l) update(l,r,v,now<<1|1);
            pushup(now);
        }
        int query(int l,int r,int now = 1){
            //cerr<<l<< ' '<<r<<' '<<now<<'$'<<nd.l<<' '<<nd.r<<'
    ';
            if(l<=nd.l&&r>=nd.r) return nd.v;
            int res = 0;
            pushdown(now);
            if(l<=ndl.r&&r>=ndr.l){
                res+=query(l,r,now<<1);
                res+=query(l,r,now<<1|1);
                if(ndl.cr==ndr.cl) res--;
            }
            else if(l<=ndl.r) res+=query(l,r,now<<1);
            else if(r>=ndr.l) res+=query(l,r,now<<1|1);
            pushup(now);
            return res;
        }
        int getcr(int pos,int now = 1){
            if(nd.l==nd.r) return nd.cr;
            int res = 0;
            pushdown(now);
            if(pos<=ndl.r) res = getcr(pos,now<<1);
            else res = getcr(pos,now<<1|1);
            pushup(now);
            return res;
        }
    }tree;
    void dfs(int u,int pre,int d){
        deep[u] = d,par[u] = pre,sz[u] = 1;
        forn(i,e[u].size()){
            int v = e[u][i];
            if(v==pre) continue;
            dfs(v,u,d+1);
            sz[u]+=sz[v];
            if(sz[v]>sz[son[u]]) son[u] = v;
        }
    }
    void getpos(int u,int gg){
        top[u] = gg,p[u] = ++id,fp[p[u]] = u;
        if(son[u]) getpos(son[u],gg);
        forn(i,e[u].size()){
            int v = e[u][i];
            if(v==par[u]||v==son[u]) continue;
            getpos(v,v);
        }
    }
    bool check(int x,int y){
        return tree.getcr(p[x])==tree.getcr(p[y]);
    }
    int query(int x,int y){
        int fx = top[x],fy = top[y];
        int res = 0;
        while(fx!=fy){
            if(deep[fx]<deep[fy]) swap(fx,fy),swap(x,y);
            res+=tree.query(p[fx],p[x]);
            if(check(par[fx],fx)) res--;
            x = par[fx], fx = top[x];
        }
        if(deep[x]>deep[y]) swap(x,y);
        res+=tree.query(p[x],p[y]);
        return res;
    }
    
    void change(int x,int y,int v){
        int fx = top[x],fy = top[y];
        while(fx!=fy){
            if(deep[fx]<deep[fy]) swap(fx,fy),swap(x,y);
            tree.update(p[top[x]],p[x],v);
            x = par[fx], fx = top[x];
        }
        if(deep[x]>deep[y]) swap(x,y);
        tree.update(p[x],p[y],v);
    }
    
    int main(){
        IO;
        int n,m;cin>>n>>m;
        for1(i,n) cin>>a[i];
        forn(i,n-1){
            int x,y;cin>>x>>y;
            e[x].push_back(y);
            e[y].push_back(x);
        }
        dfs(1,0,0);    
        getpos(1,1);
        tree.maketree(1,n);
        while(m--){
            char c;cin>>c;
            if(c=='Q'){
                int x,y;cin>>x>>y;
                cout<<query(x,y)<<'
    ';
            }else{
                int x,y,z;cin>>x>>y>>z;
                change(x,y,z);
            }   
        }
        return 0;
    }
    
    人一我百,人十我万。
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  • 原文地址:https://www.cnblogs.com/AlexPanda/p/12520304.html
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