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  • Codeforces 1137B(kmp next数组构造)

    为了物尽其用,Next求出最多有哪部分能重复使用,然后重复使用就行了……

    const int maxn = 5e5 + 5;
    char s[maxn], t[maxn];
    int cnts0, cnts1, cntt0, cntt1;
    int Next[maxn];
    
    int main() {
    	ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0);
    	cin >> (s + 1) >> (t + 1);
    	int lens = strlen(s + 1), lent = strlen(t + 1);
    
    	for (int i = 1; i <= lens; i++) {
    		if (s[i] == '1')	cnts1++;
    		else	cnts0++;
    	}
    
    	Next[1] = 0;
    	for (int i = 2, j = 0; i <= lent; i++) {
    		while (j > 0 && t[i] != t[j + 1])	j = Next[j];
    		if (t[i] == t[j + 1])	j++;
    		Next[i] = j;
    	}
    
    	for (int i = Next[lent] + 1; i <= lent; i++) {
    		if (t[i] == '1')	cntt1++;
    		else	cntt0++;
    	}
    
    	for (int i = 1; i <= lent; i++) {
    		if (t[i] == '1' && cnts1)	cout << 1, cnts1--;
    		else if (t[i] == '0' && cnts0)	cout << 0, cnts0--;
    	}
    	int k = min(cntt0 ? cnts0 / cntt0 : inf, cntt1 ? cnts1 / cntt1 : inf);
    	while (k--)	{
    		for (int i = Next[lent] + 1; i <= lent; i++) {
    			if (t[i] == '1')	cout << 1, cnts1--;
    			else	cout << 0, cnts0--;
    		}
    	}
    	while (cnts1--)	cout << 1;
    	while (cnts0--) cout << 0;
    	
    	return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/AlphaWA/p/10699473.html
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